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3 years ago

At the candy store there are 2,369 jelly beans in a jar . One -fourth of the jelly bean are green . About how many are green ?

Mathematics

2 answers:

miv72 [106K]3 years ago

3 0

Well sense there aren't any colors the rest is 3/4

Thepotemich [5.8K]3 years ago

3 0

Divide 2369 by 4 = 592.25 so about 592

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Find KJM <br><br><br> I NEED HELP

marissa [1.9K]

Answer:

Angle kjm is 56 °

you equate 7x with 3x +16

3x + 16 = 7x

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3 years ago

Fill in the blank to make the expression a perfect square u² - 14 u +

MissTica

12 beacause it is what it is jk im just put anything fr the challenges plz rate me 5 stars

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3 years ago

Help me please this is due in 30 mins!

snow_tiger [21]

Answer:

17 feet

Step-by-step explanation:

Since a square has 4 sides, you have to do 68 / 4 to find one of the sides.

68/4 = 17

And to check, if you add up all sides...

17+17+17+17 = 68

8 0

2 years ago

Solve the matrix equation for a, b, c, and d. [1 2] [a b] [6 5][3 4] [c d]= [19 8]

Anit [1.1K]

Answer:

The answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

Step-by-step explanation:

$\bold{\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]}$

Solve the L.H.S part:

$\left[\begin{array}{cc}1&2\\3&4\end{array}\right] \left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\\\\\\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]$

After calculating the L.H.S part compare the value with R.H.S:

$\left[\begin{array}{cc}a+2c&b+2d\\3a+4c&3b+4d\end{array}\right]= \left[\begin{array}{cc}6&5\\ 19&8\end{array}\right]} \\\\$

$\to a+2c =6....(i)\\\\\to b+2d =5....(ii)\\\\\to 3a+4c =19....(iii)\\\\\to 3b+4d = 8 ....(iv)\\\\$

In equation (i) multiply by 3 and subtract by equation (iii):

$\to 3a+6c=18\\\to 3a+4c=19\\\\\text{subtract}... \\\\\to 2c = -1\\\\\to c= - \frac{1}{2}$

put the value of c in equation (i):

$\to a+ 2 (- \frac{1}{2})=6\\\\\to a- 2 \times \frac{1}{2}=6\\\\\to a- 1=6\\\\\to a =6 +1\\\\\to a = 7\\$

In equation (ii) multiply by 3 then subtract by equation (iv):

$\to 3b+6d=15\\\to 3b+4d=8\\\\\text{subtract...}\\\\\to 2d = 7\\\\\to d= \frac{7}{2}\\$

put the value of d in equation (iv):

$\to 3b+4 (\frac{7}{2})=8\\\\\to 3b+4 \times \frac{7}{2}=8\\\\\to 3b+14=8\\\\\to 3b =8-14\\\\\to 3b = -6\\\\\to b= \frac{-6}{3}\\\\\to b= -2$

The final answer is " $\bold{\left[\begin{array}{cc}a&b\\c&d\end{array}\right] = \left[\begin{array}{cc}7&-2\\ -\frac{1}{2}&\frac{7}{2}\end{array}\right]}$ ".

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4 years ago

The product of seven and the difference between a number and ten

Rina8888 [55]

Answer:

7(x-10)

Step-by-step explanation:

7×(x-10)

you ×7by whatever x-10 is

6 0

4 years ago

Read 2 more answers