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Mrac [35]
3 years ago
8

PLZ HELP ASAP THANKS <3

Mathematics
1 answer:
omeli [17]3 years ago
6 0

sure how can I help?

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An Air Force plane flew to the
Free_Kalibri [48]

Answer:

5 hours

Step-by-step explanation:

Time taken for trip : t + 1

Time taken for return : t

Avg. speed (trip) : 256 km/h

Avg. speed (return) : 320 km/h

The distances covered on both trips are equal.

⇒ Distance (trip) = Distance (return)

⇒ Speed (trip) × time (trip) = Speed (return) × time (return)

⇒ (256)(t + 1) = (320)(t)

⇒ 256t + 256 = 320t

⇒ 64t = 256

⇒ t = 4 hours

<u>Time (trip)</u> = t + 1 = 4 + 1 = 5 hours

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2 years ago
Select the correct answer.
aev [14]

Answer: it’s B

Step-by-step explanation: It’s not a or c so... PERIOD

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3 years ago
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Rina8888 [55]

Answer:

Hi how are you doing today Jasmine

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Convert the angle 117 radians to degrees.
Simora [160]

Answer:

21060°

Step-by-step explanation:

117x180°

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4 0
3 years ago
Can someone help me in this plssss I really need it
kompoz [17]

Answer:

\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}

Step-by-step explanation:

Your expression is

\sqrt [3] {-54x^{5}y^{6}}

Here's how I would simplify it.

\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}

\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}

\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}

6 0
3 years ago
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