The answer should be D, divide by 6.78.
The question is incomplete, as the depth of the hook isn't given in the question. However, using a proposed depth for the hook, we could give a stepwise solution to the exercise.
Answer:
Kindly check explanation
Step-by-step explanation:
If given a hook depth of 6 meters, and a distance of 8 m(fishing line from hook) at the the Same depth, then the distance between rose and the fish, x can be calculated, using the relation.
Hypotenus² = opposite² + adjacent²
(refer to attached picture)
x² = 6² + 8²
x² = 36 +. 64
x² = 100
x = sqrt(100)
x = 10 meters
You can use the actual depth value to obtain the actual solution to your question.
Answer:
Step-by-step explanation:
y - x = -5
y = x-5
y = 2x² - 3x - 5
x-5 = 2x² - 3x - 5
2x² - 4x = 0
x² - 2x = 0
x(x - 2) = 0
x = 2, 0
(x,y) = (2,-3), (0,-5)
Answer:
3.31 x 10^4
Step-by-step explanation:
3.111 x 10^4 is 31110
2 x 10^3 is 2000
31110 + 2000 = 33100 or 3.31 x 10^4
Answer:
AE = 15 cm; ED = 18 cm; AD = 15 cm (given)
Step-by-step explanation:
ΔBEC ~ ΔAED so ...
AD/BC = AE/BE = (BE+AB)/BE = 1 + AB/BE
Substituting given numbers (lengths in centimeters), we have ...
15/10 = 1 + 5/BE
1/2 = 5/BE
BE = 10
Similarly, ...
1/2 = 6/CE
CE = 12
Then the unknown sides are ...
AE = AB + BE = 5 + 10 = 15 . . . cm
ED = CE + CD = 12 + 6 = 18 . . . cm