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Mathematics

1 answer:

shtirl [24]2 years ago

5 0

For A:

You add the probabilities to get the answer to A: = .75, or 3/4

Note that the probability of ALL THREE of them hitting would be 1/3 x 1/4 x 1/5.

For B:

2/3 and 3/4 is the probability of the other two people MISSING (the remainder of 1/3, 1/4)

1.0 = 100% chance to hit the target, so 1.0 x 2/3 x 3/4 = 1/2

Mark's chance of hitting is 1/5, so do 1/2 x 1/5, = 1/10

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slega [8]

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6 0

1 year ago

Read 2 more answers

out of 125 children at summer camp 45 signed up for swimming 38 for arts and crafts if a child is randomly selected what is the

anzhelika [568]

P(s) = 45/125 = 0.360
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Therefore,
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3 years ago

Read 2 more answers

Suppose P(A) = 0.9, P(B) = 0.3, and P(B|A) = 0.2. What is P(A|B) ?

Elenna [48]

By definition of conditional probability,

$P(B\mid A)=\dfrac{P(B\cap A)}{P(A)}\implies P(B\cap A)=0.2\cdot0.9=0.18$