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katrin2010 [14]
4 years ago
13

Complete the missing number sequence.1/4, 1/2,___, 1, 11/4​

Mathematics
1 answer:
mariarad [96]4 years ago
3 0

Answer:If the last number is 1¼ then the answer is ¾

Step-by-step explanation:

From one fraction to the other there is a difference of ¼

¼+¼=½

½+½=¾

¾+¼=1

1+¼=1¼

To identify the difference between the fractions you should get the LCM of the denominator which is 4 then you change all the fractions and make them have the same denominator

½ ,²/4 ,_ ,⁴/4 ,⁵/4

Then work with the numerator

1 , 2, _ ,4 , 5,

The dash is to be filled with 3

So your answer is ¾

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Answer:

100%

Step-by-step explanation:

Perimeter of first garden is given by 2(l+w) where l is length and w is width

Perimeter=2(5+3)=16

The dimensions of second rectangle is doubled hence 10 ft by 6 ft

Perimeter=2(10+6)=32

Change in area will be 32-16=16

Percentage change in area is 16/16*100=100%

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Answer:

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3 years ago
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Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

6 0
3 years ago
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Ghella [55]

Answer:

The answer is B. 1,620

Step-by-step explanation:

I just know it did the math

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3 years ago
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