Question

what is the equation of the line in standard form? please help me I am really having a hard time with this

Answer 1

2x - y = 2

obtain the equation of the line in slope-intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (2, 2 ) and (x₂, y₂ ) = (- 1, - 4) ← 2 points on the line

m = $\frac{-4-2}{-1-2}$ = $\frac{-6}{-3}$ = 2

the line crosses the y-axis at (0, - 2 ) ⇒ c = - 2

y = 2x - 2 ← in point-slope form

the equation of a line in standard form is

Ax + By = C ( A is a positive integer and B, C are integers )

rearrange y = 2x - 2 into this form

subtract y from both sides

0 = 2x - y - 2 ( add 2 to both sides )

2x - y = 2 ← in standard form

Answer 2

Answer:

      -4 - 2

m= --------- (over)

      -1 - 2

Step-by-step explanation: