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Salsk061 [2.6K]
3 years ago
12

You can buy 5 cans of green beans at the village market for $2.30. You can buy 10 of the same cans of green beans at Sams Club f

or $4.30. Which place is the better buy?
Mathematics
2 answers:
sineoko [7]3 years ago
5 0
Find the price per can for each place. Village Market: $2.30/5 cans = $0.46 per can. Sam's Club: $4.30/10 cans = $0.43 per can.  $0.43 per can at Sam's Club is less than $0.46 per can at Village Market, so Sam's Club is the better buy.
Bezzdna [24]3 years ago
5 0
At sams club beacause if you were to multiply the price of 5 cans by two you would get 4.60.anf at sams club it's 4.30 for 10 cans
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Let the time taken by computer for virus scan be, 'x' days

We are given that Computer A runs a virus scan in every 2.75 days and Computer B runs a virus scan in every 3.5 days.

<h3>Amount of work done by computer A⤵️</h3>

Amount of work done in one day = \tt\frac{1}{2.75}

Amount of work done in x days = \tt\frac{x}{2.75}

<h3>Amount of work done by Computer B⤵️</h3>

Amount of work done in one day = \tt\frac{1}{3.5}

Amount of work done in x days = \tt\frac{x}{3.5}

Since, They are doing the same work the amount of work done is 1.

\sf \:  \frac{x}{2.75}  +  \frac{x}{3.5}  = 1

Solve for x ~

\sf \frac{x}{ \frac{11}{4} }  +  \frac{x}{ \frac{7}{2} }  = 1

\sf \frac{4x}{11}  +  \frac{2x}{7}  = 1

\sf \: 28x + 22x = 77

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\boxed{ \bf \: x = 1.54}

➪ <em>Thus, the time taken when both computers run a virus scan at the same time again is, 1.54 days</em>

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2 years ago
Tommy can ride his bicycle 4.5 miles in 15 minutes how many miles can he ride in 75 minutes
emmainna [20.7K]
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6 0
4 years ago
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This figure is made up of a quadrilateral and a semicircle.
vodomira [7]

Here the figure is made up of a quadrilateral and a semi circle.

ABCD is the quadrilateral here. We will find the sides of the quadrilateral by using the distance formula.

If (x₁, y₁) and (x₂, y₂) are two points given, then the distance between two points by using distance formula is,

d =\sqrt({ x_{1}-x_{2})^2  +( y_{1} -y_{2}  )^2}

The co-ordinate of A is (-1,2) and co-ordinate of B is (-2,-1).

So the length of side AB = \sqrt{(-1-(-2))^2+(2-(-1))^2}

=\sqrt{(-1+2)^2+(2+1)^2}(As negative times negative is positive)

= \sqrt{(1)^2+(3)^2} =\sqrt{1+9}  =\sqrt{10}

The co-ordinate of C is (4,-3) and D is (5,0)

The length of side CD

= \sqrt(4-5)^2+(-3-0)^2}

= \sqrt{(-1)^2+(-3)^2}

= \sqrt{1+9} =\sqrt{10}

So the sides AB and CD are equal.

The length of side AD

= \sqrt{(-1-5)^2+(2-0)^2}

= \sqrt{(-6)^2+(2)^2} =\sqrt{36+4} =\sqrt{40}

The length of side BC

= \sqrt{(-2-4)^2+(-1-(-3))^2}

= \sqrt{(-2-4)^2+(-1+3)^2}

= \sqrt{(-6)^2+(2)^2}=\sqrt{36+4} =\sqrt{40}

So the lengths of the sides AD and BC are equal.

So the quadrilateral is a rectangle whose length is \sqrt{40} and width is \sqrt{10}.

Area of a rectangle = length × width

= (\sqrt{40}) (\sqrt{10})

= \sqrt{(40)(10)}=\sqrt{400}

= 20 unit^2

Now the diameter of the semicircle is the side AD = \sqrt{40}

So, the radius of the semi-circle = \frac{\sqrt{40}}{2}

= \frac{\sqrt{(4)(10)}}{2}

= \frac{(\sqrt{4})(\sqrt{10})}{2}

= \frac{2\sqrt{10}}{2} = \sqrt{10}

Area of semi-circle = \frac{1}{2} \pi r^2, where r is the radius.

= \frac{1}{2} \pi  (\sqrt{10})^2

= \frac{1}{2} \pi   (10)

= \frac{(\pi)(10)}{2}

= \frac{10\pi}{2}   = 5\pi = 15.7 unit^2 ( Approximately taken to the nearest tenth)

Total area of the figure = (20+15.7) unit^2 = 35.7 unit^2

We have got the required answer.

Option a is correct here.

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Step-by-step explanation:

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8 0
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