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lord [1]
3 years ago
6

Factor 2x^3+6x^2-8x-24

Mathematics
1 answer:
ch4aika [34]3 years ago
5 0
"The bread-enclosed convenience food known as the "sandwich" is attributed to John Montagu, fourth Earl of Sandwich (1718-1792), a British statesman and notorious profligate and gambler, who is said to be the inventor of this type of food so that he would not have to leave his gaming table to take supper.
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Write an expression to represents the product of 6 and the sum of w and 5
muminat
6(w+5) represents the product of 6 and the sum of w and 5. the product means multiplication, and the sum means addition.

6(w+5) also equals 6w+6(5), or 6w+30, because of the distribution property.
6 0
3 years ago
Please help with this
Licemer1 [7]
A. 10p (10 dollars per photo)
b. 75-5
sorry but I can't remember how to do c.:(
6 0
3 years ago
What is the probability of the complement of rolling a number less than 5 by using a six-sided die?
Inessa05 [86]
<h3><u>Answer:</u></h3>

Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is:

1/3

<h3><u>Step-by-step explanation:</u></h3>

Let A denote the event of rolling a number less than 5 in a six-sided die.

Now, we know that the Total outcomes are: 6

since, the sample space is given as: {1,2,3,4,5,6}

Also Number of favorable outcomes are: 4

since the numbers which are less than 5 are {1,2,3,4}

Now we have to find:

P(A^c)

where P denotes the probability of an event and A^c denote the complement of event A.

We know that:

P(A^c)=1-P(A)

Now,

P(A)=\dfrac{4}{6}\\\\P(A)=\dfrac{2}{3}

Hence,

P(A^c)=1-\dfrac{2}{3}\\\\P(A^c)=\dfrac{3-2}{3}\\\\P(A^c)=\dfrac{1}{3}

Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is:

1/3

8 0
4 years ago
Read 2 more answers
(25 POINTS)(PLEASE HELP) A young sumo wrestler decided to go on a special diet to gain weight rapidly. He gained weight at a con
myrzilka [38]

Answer: Answer might be 4.2 kilograms per month

Step-by-step explanation: I know that the main pattern is 7.8 kilos in 1.5 months, so I divided that by three to get 3 0.5s ( 2.6 ) and added two of dems together for one solid 4.2 kilograms as a answer.

I don't know for sure ( just woke up ) but hope this helps!

4 0
3 years ago
Read 2 more answers
Write the equation of a line that passes through (-2, 0) and (3, 10).
Allisa [31]

Answer:

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(-2,0) and (3,10).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (-2,0), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=-2 and y1=0.

Also, let's call the second point you gave, (3,10), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=3 and y2=10.

Now, just plug the numbers into the formula for m above, like this:

m=  

10 - 0

3 - -2

or...

m=  

10

5

or...

m=2

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=2x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(-2,0). When x of the line is -2, y of the line must be 0.

(3,10). When x of the line is 3, y of the line must be 10.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=2x+b. b is what we want, the 2 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (-2,0) and (3,10).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(-2,0). y=mx+b or 0=2 × -2+b, or solving for b: b=0-(2)(-2). b=4.

(3,10). y=mx+b or 10=2 × 3+b, or solving for b: b=10-(2)(3). b=4.

See! In both cases we got the same value for b. And this completes our problem.

8 0
3 years ago
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