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VashaNatasha [74]
3 years ago
9

Consider the following code example:

Computers and Technology
1 answer:
yKpoI14uk [10]3 years ago
7 0

Answer:

The number of invoices for each vendor that have a larger balance due than the average balance due for all invoices.

Explanation:

This part of the code below

WHERE InvoiceTotal - PaymentTotal - CreditTotal >

(SELECT AVG (InvoiceTotal - PaymentTotal- CreditTotal)

FROM Invoices)

gives the condition to pick the invoices with balance that are greater than the average balance for all invoice.

This part of the code below

GROUP BY VendorName

ORDER BY BalanceDue DESC;

then enables the program to group the result of the above condition by VendorName and sort the resulting rows in the order of BalanceDue. You will therefore, obtain for each row in the NumberOfInvoices column, the number of invoices for each vendor that have a larger balance due than the average balance due for all invoices.

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Answer:

All of the above.

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3 years ago
The algorithm for solving the problem of average of five (5) numbers​
PilotLPTM [1.2K]

Answer:

Explanation:

Denote the five numbers as a, b, c, d and e.

The average is:

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Easily:

Learn how to do input and output operations in your programming language of choice.

Learn what average is (see Arithmetic mean - Wikipedia)

Learn how to code arithmetic operations in your PL of choice.

Put all that together and code the program.

Oh, did you expect the code snippet? Sorry, I don’t do peoples’ homework for them on principle. Homework is for you to learn something. If you can’t be bothered, accept that you’ll fail your class. If you want to pass, LEARN.

3 0
3 years ago
3.26 LAB: Leap Year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate a
Tju [1.3M]

Answer:

year = int(input("Enter a year: "))

if (year % 4) == 0:

  if (year % 100) == 0:

      if (year % 400) == 0:

          print(str(year) + " - leap year")

      else:

          print(str(year) +" - not a leap year")

  else:

      print(str(year) + " - leap year")

else:

  print(str(year) + "- not a leap year")

Explanation:

*The code is in Python.

Ask the user to enter a year

Check if the <u>year mod 4</u> is 0 or not. If it is not 0, then the year is not a leap year. If it is 0 and if the <u>year mod 100</u> is not 0, then the year is a leap year. If the <u>year mod 100</u> is 0, also check if the <u>year mod 400</u> is 0 or not. If it is 0, then the year is a leap year. Otherwise, the year is not a leap year.

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What is 9 - 3 ÷ 1/3 + 1 = ?
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The answer is 9
Hope I helped you
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