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Len [333]
3 years ago
9

Write a quadratic equation with the given roots write the equation in the form ax^2+bx+c=0 where a,b,and c are integers -5/4 and

8
Mathematics
1 answer:
Alecsey [184]3 years ago
8 0
To form the quadratic equation, form II equations;
(x-(\frac{-5}{4})(x-8)=0
(x+\frac{5}{4} )(x-8)=0
Open the brackets;
x(x-8)+\frac{5}{4}(x-8)=0
x^{2} -8x+ \frac{5}{4} x-10=0
x^{2} - \frac{32}{4} x- \frac{5}{4} x-10=0
x^{2} - \frac{27}{4} x-10=0
This can be simplified to;
4x^{2} -27x-40=0
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4g−124, g, minus, 12 when g=5g=5
allsm [11]

Answer:

4g-124= -104, g-12= -7

Step-by-step explanation:

g=5

4g-124= ?     g-12

4(5)-124         5-12

4(5)= 20        5-12= -7

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4 0
4 years ago
A parabola intersects the x-axis at x=3 and x=9 what is the x-coordinate of the parabola's vertex?
KiRa [710]

Here we are given the x intercepts at x=3 and x=9

So let us try to make quadratic equation for this using given information.

We have factors in the form (x-a)(x-b)

where a and b are x intercepts given to us.

So rewriting in factored form:

y=(x-3)(x-9)

Now let us simplify it:

y=x^{2}-12x+27

Let us find the vertex now,

For a quadratic equation of the form:

y=ax^{2}+bx+c

For x coordinate , we have the formula,

x=\frac{-b}{2a}

So using this formula for our equation,

x=\frac{-(-12)}{2(1)}

So x = 6

Answer: The x-coordinate of the parabola's vertex is 6.


7 0
3 years ago
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Antonio is going to the carnival. He can spend no more than $20.00. if the ticket to in is $7.50, and each ride cost $1.25, how
fgiga [73]
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Step-by-step explanation:

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