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kipiarov [429]
3 years ago
7

ALGEBRA 2, PLEASE HELP ME

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

Multiply both sides of the equation in Part I by (cos theta)^2.

This will result in (cos theta)^2 + (sin theta)^2 = 1.

(Recall that (sec theta)*(cos theta) = 1.)

____ [38]3 years ago
4 0

I believe the answer is cos^2 theta. Sec^2 theta on the right side of the equation is the inverse of Cos^2 theta, so multiplying the two together will get you 1. Cos^2 theta * Tan^2 theta = Sin^2 theta, and Cos^2 theta * 1 = Cos^2 theta. This all leads to the third and last step in the picture above.

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<h3>Answer:</h3>

42.  29°

43.  3x³ +2x² -3x +10

44.  20a² +68a

<h3>Step-by-step explanation:</h3>

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3 years ago
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P- (-5, -6)

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