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kipiarov [429]
3 years ago
7

ALGEBRA 2, PLEASE HELP ME

Mathematics
2 answers:
jeka57 [31]3 years ago
8 0

Multiply both sides of the equation in Part I by (cos theta)^2.

This will result in (cos theta)^2 + (sin theta)^2 = 1.

(Recall that (sec theta)*(cos theta) = 1.)

____ [38]3 years ago
4 0

I believe the answer is cos^2 theta. Sec^2 theta on the right side of the equation is the inverse of Cos^2 theta, so multiplying the two together will get you 1. Cos^2 theta * Tan^2 theta = Sin^2 theta, and Cos^2 theta * 1 = Cos^2 theta. This all leads to the third and last step in the picture above.

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If (9x − 4)(9x + 4) = ax² − b, what is the value of a? (5 points)
lions [1.4K]

Given, (9x - 4)(9x + 4) = ax² - b

From algebraic identities:

We know, (a + b)(a - b) = a² - b²

Now, 81x² + 36x - 36x - 16 = ax² - b

81x² - 16 = axis² - b

So ax² = 81x²

a = 81

-b = -16

b = 16

Solution

Therefore, the value of a is 81.

<h2>MyHeritage</h2>
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2 years ago
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3 years ago
2x + y = -2
cupoosta [38]
Answer is A
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2 years ago
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4/6 + 1/12. Quick answer.
Fynjy0 [20]

nvm lol 3/4( had to redo

6 0
3 years ago
I need help with multiplying polynomials using foil<br><br> Example <br> (X+5)(x-6)
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3 0
3 years ago
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