The solutions or roots to this equation is found by solving for x. We can do this a couple ways either by FOIL or quad formula
3x^2+6x+6=0
3(x^2+2x+2)=0
x^2+2x+2=0 we cant FOIL this out so we use the quad formula
x= [(-b+\-sqrt(b^2-4ac))/2a]
x= -2+\- sqrt(4-4(1)(2))/2(1)
x= -1 +i , -1 - i
So we have complex roots since our quad formula returned a negative number. Whenever the quad formula answer is positive we have two roots/solutions, when it is zero we have one root/solution, and whenever it is negative we have Complex roots/solutions
Hope this helps. Any questions please just ask. Thank you.
Answer:
Below.
Step-by-step explanation:
{ a1 = 0.5
{ an = an-1*(-0.2)
The first 4 terms are:
= 0.5, -0.1, 0.02, -0.004
Answer:
Distribute 1.2 to 6.3 and -7x
Combine 3.5 and 7.56
suhtract 11.06 from both sides
Answer:
-8
Step-by-step explanation:
