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dmitriy555 [2]
3 years ago
14

Help with the above

Mathematics
1 answer:
Veseljchak [2.6K]3 years ago
7 0

Answer:

B

Step-by-step explanation:

It is not A because if they were riding for a constant speed the entire ride it would just be a straight line going up and that line is curved.

It is B because in the chart you see that from hour 3 to hour 4 they did not move at all (this is why it is a flat horisontal line) and you can infer that they stopped and took a break.

It is not C because they stopped and took a break at hour 3 to hour 4.

It is not D because they never decreased their milage.

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Pls help now. Find X (picture below)
Arlecino [84]

Answer:

20

Step-by-step explanation:

18000/30=600

600/30=20

8 0
3 years ago
What is the quotient (x3 + 3x2 + 5x + 3) ÷ (x + 1)?
Anvisha [2.4K]
Hello,

Answer C

x^3+3x²+5x+3=x^3+2x²+3x + x²+2x+3=x(x²+2x+3)+1(x²+2x+3)=(x²+2x+3)(x+1)

7 0
3 years ago
Read 2 more answers
25 PTS *** Multiply and simplify. Write your answer in radical notation
marishachu [46]
\sqrt[3]{xy^5}  \sqrt[3]{x^7y^{17}}= \sqrt[3]{xy^5 \cdot x^7y^{17}}= \sqrt[3]{x^8y^{22}}= x^2y^7\sqrt[3]{x^2y}
3 0
3 years ago
Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,
stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

6 0
3 years ago
which of the following can not be probabilities? 1, -0.56, square root of 2, 3/5, 1.23, 0, 5/3, 0.02??
Katarina [22]

It is important to know that probabilities are defined insed the range [0,1], which means they cannot be outside that set of values.

<h2>Hence, -0.56, square root of 2, 1.23, and 5/3 can't be probabilities because they are outside the range of values.</h2>
3 0
1 year ago
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