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larisa86 [58]
4 years ago
6

Please help!!! Intersection of chords use formula a•b=c•d

Mathematics
1 answer:
scoray [572]4 years ago
5 0

Given:

Length of chords of one segment = 11 and 8

Length of chords of other segment = 2 and x

To find:

The value of x.

Solution:

<em>If two chords intersect each other inside a circle, the products of length their segments are equal.</em>

\Rightarrow a \cdot b =c \cdot d

\Rightarrow 11 \cdot 8 =2 \cdot x

\Rightarrow 88 =2x

Divide by 2 on both sides.

$\Rightarrow\frac{88}{2} =\frac{2x}{2}

$\Rightarrow 44 =x

Switch the sides.

$\Rightarrow x=44

The value of x is 44.

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Solve the inequality for u. 55 &gt; 4u + 15 Simplify your answer as much as possible.​
valentinak56 [21]

Step-by-step explanation:

55 > 4u + 15

40 > 4u

10 > u

so, this is true for all u < 10

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3 years ago
Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
kirza4 [7]

Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

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3 years ago
Sketch the curve y=x(x-2)^3 showing any stationary points and points of inflection
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Answer:

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6 0
3 years ago
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What is 74 divided by 9??
Rama09 [41]
Its 8.22.. the 2 repeats
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3 years ago
In order to make a service for four 1 3/4 cups of chopped vegetables are needed. Based on this information, determine the amount
Mila [183]

For this case we propose a rule of three according to the data of the statement. To do this, we convert the mixed number into an improper fraction:

1 \frac {3} {4} = \frac {4 * 1 + 3} {4} = \frac {7} {4}cups

4 ----------> \frac {7} {4}

10 ----------> x

Where the variable "x" represents the amount of chopped of vegetables needed for 10 people.

x = \frac {10 * \frac {7} {4}} {4}\\x = \frac {\frac {70} {4}} {4}\\x = \frac {70} {16}\\x = \frac {35} {8}

This is equivalent to 4 \frac {3} {8}cups.

Answer:

4 \frac {3} {8} cups

6 0
3 years ago
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