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2 years ago

Five times the result of adding one to a certain number, is equal to four times the number, plus three. Find the number

Mathematics

1 answer:

Galina-37 [17]2 years ago

5 0

Answer:

The number is -2

Step-by-step explanation:

Let the number = x

Given that:

Five times the result of adding one to a certain number, is equal to four times the number, plus three.

The equation will be:

5(x+1) = 4x +3

Simplifying

5x + 5 = 4x +3

Taking terms with x on left side and others on right side

5x - 4x = 3 - 5 (sign of transferred terms will be changed)

x = -2

Proof :

Condition 1:

number = -2

Add one = -2 +1 = -1
Multiply 5 = -5

Condition 2:

4 times of number = 4 (-2) = -8
Add 3 = -8 +3 = -5

Hence both conditions have same answer.

I hope it will help you!

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Pls help me

gizmo_the_mogwai [7]

Answer:

yes yes

Step-by-step explanation:

not 100% but it should be right

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2 years ago

21x =7?<br> A. x=3<br> B. None of these <br> C. x=147<br> D. x=28

Varvara68 [4.7K]

Answer: B

Step-by-step explanation:

To isolate x, you divide both sides by 21

21x=7

$\frac{21x}{21}=\frac{7}{21}$

x = 7/21

Simplify by dividing both the numerator and denominator by 7

x = 1/3

Since, 1/3 is not an option, B is the correct answer

6 0

1 year ago

May someone help me with this problem?

Katyanochek1 [597]

Answer:

$a. \: \: \frac{ {4x}^{6} }{ {y}^{3} } \\$

$b. \: \: \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

Step-by-step explanation:

${( {4x}^{ - 2} y)}^{ - 3} \\ {4x}^{ - 2 \times - 3} \: \: {y}^{1 \times - 3} \\ {4x}^{6} {y}^{ - 3} \\ \frac{ {4x}^{6} }{ {y}^{3} } \\$

${( {8x}^{6} {y}^{ - 3}) }^{ \frac{1}{2} } \\ {8x}^{6 \times \frac{1}{2} } \: \: {y}^{ - 3 \times \frac{1}{2} } \\ {8x}^{3} {y}^{ - \frac {3}{2} } \\ \frac{ {8x}^{3} }{ {y}^{ 1\frac{1}{3} } } \\$

7 0

2 years ago

There are 4 red and 6 green marbles in a jar. What is the probability of drawing two green marbles, with replacement?

quester [9]

Answer:

3/5

Step-by-step explanation:

4+6=10

6/10=3/5

3 0

3 years ago

Find the least common multiple of each pair of polynomials.<br> 5 y² - 80 and y + 4

kobusy [5.1K]

The least common multiple of each pair of the polynomial (5y² - 80) and

(y + 4) is equal to 5(y-4)(y+4).

As given in the question,

Given pair of the polynomial is (5y² - 80) and (y + 4)

Simplify the given polynomial using (a² -b²) = (a-b)(a +b)

(5y² - 80) = 5(y² -16)

⇒(5y² - 80) = 5(y² - 4²)

⇒(5y² - 80) = 5(y -4)(y + 4)

And (y + 4) = (1) (y+4)

Least common multiple = 5(y-4)(y+ 4)

Therefore, the least common multiple of the given pair of the polynomial is 5(y -4)(y+ 4).

Learn more about least common multiple here

brainly.com/question/11533141

#SPJ4

6 0

1 year ago