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3 years ago

I need Smart people:)

Mathematics

1 answer:

Blababa [14]3 years ago

7 0

Answer:

What? I do not even see what you are trying to get at. I have a masters in math so I could help. Whats the question you are having an issue with ?

Step-by-step explanation:

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Can someone explain? I Dont Get It

Rama09 [41]

A

Because A dictates the actual equation correctly

6 0

3 years ago

What the answer to this asap

Kitty [74]

Answer:

? is 24

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

2. If Mrs. Esposito drove 585 miles to North Carolina in 9 hours, what speed was she driving? (miles per hour) a. 55 mph b. 60 m

vekshin1

Your answer is 65

Step-by-step explanation:

You need to divide 585 by 9 the answer is 65

3 0

3 years ago

We have n = 100 many random variables Xi ’s, where the Xi ’s are independent and identically distributed Bernoulli random variab

777dan777 [17]

Answer:

(a) The distribution of $X=\sum\limits^{n}_{i=1}{X_{i}}$ is a Binomial distribution.

(b) The sampling distribution of the sample mean will be approximately normal.

Step-by-step explanation:

It is provided that random variables $X_{i}$ are independent and identically distributed Bernoulli random variables with p = 0.50.

The random sample selected is of size, n = 100.

(a)

Theorem:

Let $X_{1},\ X_{2},\ X_{3},...\ X_{n}$ be independent Bernoulli random variables, each with parameter p, then the sum of of thee random variables, $X=X_{1}+X_{2}+X_{3}...+X_{n}$ is a Binomial random variable with parameter n and p.

Thus, the distribution of $X=\sum\limits^{n}_{i=1}{X_{i}}$ is a Binomial distribution.

(b)

According to the Central Limit Theorem if we have an unknown population with mean μ and standard deviation σ and appropriately huge random samples (n > 30) are selected from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

The sample size is large, i.e. n = 100 > 30.

So, the sampling distribution of the sample mean will be approximately normal.

The mean of the distribution of sample mean is given by,

$\mu_{\bar x}=\mu=p=0.50$

And the standard deviation of the distribution of sample mean is given by,

$\sigma_{\bar x}=\sqrt{\frac{\sigma^{2}}{n}}=\sqrt{\frac{p(1-p)}{n}}=0.05$

(c)

Compute the value of $P(\bar X>0.50)$ as follows:

$P(\bar X>0.50)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{0.50-0.50}{0.05})\\$

$=P(Z>0)\\=1-P(Z$

*Use a z-table.

Thus, the value of $P(\bar X>0.50)$ is 0.50.

8 0

3 years ago

A video game system costs $185 and one video game costs $14.95. You can spend no more than $280 on the system and games. set up

disa [49]

Answer:

Therefore the maximum number of video games that we can purchase

is 6.

Step-by-step explanation:

i) Let us say the number of video game system we can buy that costs $185

is x and the number of video games of cost $14.95 is y.

ii) The total amount we can spend on the purchase of the video game

system is $280.

iii) Now with the amount of $280 mentioned in ii) we can see that the

number of game systems that can be bought is 1.

Therefore x = 1.

Therefore the equation we can write to equate the number of video

games and video game system is given by $185 + $14.95 × y ≤ 280

Therefore 14.95 × y ≤ 280 - 185 = 95

Therefore y ≤ 95 ÷ 14.95 = 6.355

Therefore the maximum number of video games that we can purchase

is 6.

5 0

3 years ago