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4 years ago

8

Please help !!

1 answer:

MAVERICK [17]4 years ago

5 0

Answer:

see explanation

Step-by-step explanation:

(1)

Calculate the slope m using the slope formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (0, 3) and (x₂, y₂ ) = (4, 0) ← 2 points on the line

m = $\frac{0-3}{4-0}$ = - $\frac{3}{4}$

(2)

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

note the line crosses the y- axis at (0, 3) ⇒ c = 3

y = - $\frac{3}{4}$ x + 3 ← equation of line

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dmitriy555 [2]

Answer:

84

Step-by-step explanation:

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3 years ago

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What is the ratio 15 to 35 written as a fraction in lowest terms?

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3 years ago

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GRADE 6 MATHEMAT 12. Look at the data set. 12, 34, 27, 27, 36, 42, 15, 28, 32, 47, 30 Which statement is true about the data set

adelina 88 [10]

The statement is true because it's going in accending order.

the prerquartute 11 question

Step 1: Put the numbers in order.

1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 2: Find the median.

1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.

Step 3: Place parentheses around the numbers above and below the median.

Not necessary statistically, but it makes Q1 and Q3 easier to spot.

(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).

Step 4: Find Q1 and Q3

Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.

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3 years ago

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Zepler [3.9K]

Answer:

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Step-by-step explanation:

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kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

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3 years ago