Question

Find the perimeter of the shape below:

Answer 1

Add all sides


use distance formula to fnd distance: sqrt((x1-x2)^2+(y1-y2)^2)
if is wrong,i'm sorry,i think this is right

Answer 2

Answer:

Perimeter = 13.27 unit

Step-by-step explanation:

We have to find the perimeter of the shape given in the figure.

Coordinates of J are ( -3, 4 ) and K are (-1, 6)

Then JK = $\sqrt{(x-x')^{2}+(y-y')^{2}}$

              = $\sqrt{(-3+1)^2+(6-4)^2}$

             = $\sqrt{4+4}$

             = $2\sqrt{2}$

Coordinates of K are (-1,6) and for ∠ are (1, 1)

KL = $\sqrt{(1+1)^2+(1-6)^2}$

     = $\sqrt{2^2+5^2}$

     = $\sqrt{29}$

Coordinates of M are (-1, 3) and of ∠ are (1, 1)

∠M = $\sqrt{(1+1)^2+(1-3)^2}$

      = $\sqrt{4+4}$

      =  $2\sqrt{2}$

Coordinates of M are (-1, 3) and J are (-3, 4)

MJ = $\sqrt{(-1+3)^2+(3-4)^2}$

     =  $\sqrt{4+1}$

     =  $\sqrt{5}$

Then perimeter = JK + KL + LM + MJ

                          =  $2\sqrt{2}$ + $\sqrt{29}$ +  $2\sqrt{2}$ +  $\sqrt{5}$

                         =  $4\sqrt{2}$ +  $\sqrt{29}$  +  $\sqrt{5}$

                        = 5.66 + 5.38 + 2.24 = 13.27