Given :
An expression (cos 6m)(cos 2m) .
To Find :
We need to express it in terms as sum or difference.
Solution :
We know,
cos( A + B ) = cosA cos B - sin A sin B
cos( A - B ) = cosA cos B + sin A sin B
Adding both the equations we get :
2cos A cos B = cos( A + B) + cos( A - B )
or
cos A cos B = cos( A + B) + cos( A - B )/2
Putting value of A = 6m and B = 2m in above equation, we get :
(cos 6m)(cos 2m) = cos( 6m + 2m ) + cos( 6m - 2m )/2
(cos 6m)(cos 2m) = cos(8m) + cos(4m)/2
Hence, this is the required solution.
I'll just factor the above equation.
x² + 18x + 80
x² ⇒ x * x
80
can be:
1 x 80
2 x 40
4 x 20
5 x 16
8 x 10 Correct pair
(x+8)(x+10)
x(x+10) +8(x+10) ⇒ x² + 10x + 8x + 80 = x² + 18x + 80
x+8 = 0
x = -8
x+10 = 0
x = -10
x = -8
(-8)² + 18(-8) + 80 = 0
64 - 144 + 80 = 0
144 - 144 = 0
0 = 0
(-10)² + 18(-10) + 80 = 0
100 - 180 + 80 = 0
180 - 180 = 0
0 = 0
I think the algebra tiles will not be a good tool to use to factor the quadratic equation because the equation is not a perfect square quadratic equation.
Answer:
72ft
Step-by-step explanation:
Answer:
35
Step-by-step explanation:
