we know that
Perimeter of a triangle is equal to
P=a+b+c
where
a,b and c are the length sides of the triangle
<u>Find the perimeter of the triangles</u>
<u>Triangle N 1</u>
P=(x-2)+(x)+(3x+1)-------> P=5x-1
<u>Triangle N 2</u>
P=(2x-5)+(x+4)+(6x-7)------> P=9x-8
equate the perimeters
5x-1=9x-8--------> 9x-5x=-1+8-------> 4x=7
x=7/4------> x=1.75
therefore
the answer is
x=1.75
Step-by-step explanation:
18. y-(-2) = -6(x-2)
y+2 = -6x+12
y = -6x+12-2
y = -6x+10
19. y-(-4) = -½(x-4)
y+4 = -½x+2
y = -½x+2-4
y = -½x-2
Answer:
x = .06418
Step-by-step explanation:
2 + (9.2)−8x = 2.32
(9.2)−8x = 2.32 − 2
log (9.2)−8x = log .32
−8x log 9.2 = log .32
−8x log 9.2
−8 log 9.2
=
log .32
−8 log 9.2
x = .06418
Answer:
13 + 14 + 15
Step-by-step explanation:
n + (n + 1) + (n +2) =42
n + n + n + 1 + 2 = 42
3n + 3 = 42
(subtract 3 from both sides)
3n = 39
(divide both sides by 3)
n = 13
(solve)
n + (n + 1) + (n +2) =42
13 + (13 + 1) + (13 + 2) = 42
13 + (14) + (15) = 42
13, 14, 15
(Hope this helps, have a nice day!)
