With amounts measured in gallons, let
x = amount of 65% antifreeze
y = amount of 90% antifreeze
1 gal of the 65% brand contains 0.65 gal of pure antifreeze; x gal would contain 0.65x gal. Similarly, y gal of the 90% brand contains 0.90y gal of pure antifreeze.
To obtain 120 gal of 80% antifreeze solution (which contains 0.80•120 = 96 gal of pure antifreeze), we must have
x + y = 120 … … … … … [total volume of antifreeze solution]
0.65x + 0.90y = 96 … [total volume of pure antifreeze]
Solve the first equation for y :
y = 120 - x
Substitute this into the second equation and solve for x :
0.65x + 0.90 (120 - x) = 96
0.65x + 108 - 0.90x = 96
0.25x = 12
x = 48
Solve for y :
y = 120 - 48
y = 72
Answer:
A
Step-by-step explanation:
5/4*4/13=20/182=10/91 you take the red marble out so you -1 from the red and the total bag of marbles then you multiply them to gather to get the combined average then simplify
Really hope i'm right
1st row
the first one is length less than 10
one next to it is width greater than 5
next to that is length greater than 10
2nd row
the first one is length greater than 10
one next to that is width less than 5
next to that is width greater than 5
3rd row
first one is width less than 5
and last is length less than 10
Answer:
Step-by-step explanation:
We will use the co-function identity for sine, where:
Since sin(21)=0.358=cos(x). This means that:
Solve for x. Add x to both sides:
Subtract 21 from both sides:
Hence:
2a+1 + 3a+2 +5a-9 you would start by combining like terms
2a+3a+5a= 10a
1+2-9= -6
10a-6=94
then subtract 94-6=88
then divide 88 by 10= 8.8
a=8.8
