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yulyashka [42]
3 years ago
15

the admission fee at the amusement park is $3.00 for children and 6.40 fo adults on a certain day 275 people entered the park an

d the admission fees collected totaled $1284 how many children and adults were admitted
Mathematics
2 answers:
Sonbull [250]3 years ago
5 0
Children=x
Adults=y
* x + y =275 => x = 275 - y
* 3.00x + 6.40y = 1284 <=> 3.00(275 - y) + 6.40y = 1284 <=> ... <=> y = 135 => x = 275 - 135 = 140
Children: 140
Adults: 135
Zina [86]3 years ago
3 0

Let the variables be c and a.


c+a = 275 (people)

($3/child)(c) + ($6.40/adult)(a) = $1284


Solve c+a = 275 for c and subst. the result into the other equation, to eliminate the variable c:


c = 275-a

Then 3(275-a) +6.40(a) = 1284, or 825 - 3a + 6.40a = 1284

Combining like terms: 9.40a = 459. Then, a = 459/9.40 = 48.83


This makes no sense. I've checked these calculations for errors twice. Would you please go back and ensure that you have copied down the original problem completely and accurately? Thanks.



combining like terms, we get 459 = 9.40a. Solving for a: a = 459/9.40 =

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