Answer:
An=10^n + 1 is the expression for the nth term.
Next three terms:
100001
1000001
10000001
Step-by-step explanation:
The number ot 0's imcrease between the two 1's starting at no zeros, 1 zero, two zeros, and so on...
So the next terms are 100001, 1000001, 10000001 and that's without finding the formula.
Now let's find the formula:
A1=11=10+1
A2=101=100+1
A3=1001=1000+1
Notice we have increasing powers of 10 and then just adding 1.
A1=10^1 +1
A2=10^2 +1
A3=10^3 +1
....
An=10^n +1
Answer:
The answer is C
Step-by-step explanation:
I took the test
I believe the answer is 5/8
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The range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
<h3>Range</h3>
Given
592<x1317
74.35+.25
Hence:
Lowest range
74.35+.25(600-592)
74.35+.25(8)
74.35+2
=76.35
Highest range
74.35+.25(700-592)
74.35+.25(108)
74.35+27
=101.35
Range
76.35<x<101.35
Therefore the range that the amount withheld vary if the weekly wages, after subtracting withholding allowances, vary from $600 to $700 inclusive is: 76.35<x<101.35.
Learn more about range here: brainly.com/question/2264373
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