Answer:
580
Step-by-step explanation:
2 because 3 meters is labor 6 feet and 2 is above 5'9'' so it's kinda understandable
Answer:
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Step-by-step explanation:
Statement is incorrect. Correct form is presented below:
<em>The height </em>
<em> of an ball that is thrown straight upward from an initial position 3 feet off the ground with initial velocity of 90 feet per second is given by equation </em>
<em>, where </em>
<em> is time in seconds. After how many seconds will the ball be 84 feet above the ground. </em>
We equalize the kinematic formula to 84 feet and solve the resulting second-order polynomial by Quadratic Formula to determine the instants associated with such height:
(1)
By Quadratic Formula:
, 
The ball will be 84 feet above the ground 1.125 seconds and 4.5 seconds after launch.
Solve for x given two sides
Solution
x is an angle hence we are gonna use the formula Sin
Sin 0 = opp/hyp
0 represents theta.
Sin 0 = opp/hyp
Sin 0 = 27/33
Put 27/33 in decimal form
= 0.8181
Transpose to make 0 the subject
Sin 0 = 0.8181
0 = Sin-1 0.8181
When adding Sin from one side to another it becomes Sin inverse.
0 = Sin-1 08181
Now we find the answer
0 = Sin-1 0.8181
= 54.89 degrees
Therefore x is equal to 54.9 to the nearest tenth.
Answer:
13, 21
Step-by-step explanation:
Add 8 to the next number from the left to the right.
