Answer: -1.30059145
0.650295724+1.12634523i
−1.30059145
0.650295724−1.12634523i
Step-by-step explanation:
I think you would just have to find the square roots
Answer:
The probability that carbon emissions from the factory are within the permissible level and the test predicts the opposite to be true is 19.338% (Rounding to the next thousandth place)
Step-by-step explanation:
1. Let's review the information provided to us to answer the question correctly:
Probability that carbon emissions from the company’s factory exceed the permissible level = 35% = 0.35
Accuracy of the test of emissions level = 85% = 0.85
2. The probability that carbon emissions from the factory are within the permissible level and the test predicts the opposite to be true is?
These two events, carbon emissions from the company’s factory and the accuracy of the test are independent events, therefore:
Probability that carbon emissions from the factory are within the permissible level = 1 - 0.35 = 0.65
Probability that the test predicts the opposite to be true = 0..35 * 0.85 = 0.2975 (The opposite is that the carbon emissions from the company exceed the permissible level)
Probability that carbon emissions from the factory are within the permissible level and the test predicts the opposite to be true is:
0.65 * 0.2975 = 0.193375
The probability that carbon emissions from the factory are within the permissible level and the test predicts the opposite to be true is 19.338% (Rounding to the next thousandth place
MARK BRAINLIEST PLS
<span>7x^2 + 7y^2 - 28x + 42y - 35 = 0.
⇒ </span><span>x^2 + y^2 - 4x + 6y - 5 = 0.
⇒ (x-2)^2 + (y+3)^2 = 18
1. B
2. C
3. B
</span>
if we were to place <5, 12> in standard position, so it'd be originating from 0,0, then the rise is 12 and the run is 5.
so any other vector that has a negative reciprocal slope to it, will then be perpendicular or "orthogonal" to it.
so... for example a parallel to <-12, 5> is say hmmm < -144, 60>, if you simplify that fraction, you'd end up with <-12, 5>, since all we did was multiply both coordinates by 12.
or using a unit vector for those above, then
