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kirza4 [7]
3 years ago
6

A competent bacterial strain with genes a, b, and c is transformed by a donor bacterial fragment. Cotransformation frequencies f

or each gene pair are as follows: a and b 0.04% a and c 0.02% b and c 0.0064% Which conclusion can be definitively made from this data?
a) Genes b and c are farthest apart.
b) Gene order is a, b, then c.
c) Gene a is closer to c than to b.
d) Gene b is closer to c than to a.
e) Cotransformation of b and c is so frequent, they must be one gene
Biology
1 answer:
mina [271]3 years ago
4 0

Answer:

a) Genes b and c are farthest apart.

Explanation:

Transformation occurs when a competent bacteria cell takes up genetic material from the environment. Usually a donor cell donates its gene fragment  which is then incorporated into the chromosome or plasmid of recipient bacterial cell.

Cotransformation occurs when two genes are taken up together by the recipient. The closer the genes lie to each other, more are the chances of them being taken up together. Contransformation frequency will be higher if two genes are close to each other. Here, cotransformation frequencies between three genes are given. Amongst them, the lowest frequency is 0.0064% which is present between gene b and c. Hence, gene b and c are the farthest apart.

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The reason of the drought was diminished rain falls from last three third consecutive year in the region. Humans were somewhere responsible for the drought and less rainfall because this was caused by expansion of deforestation into the Amazon basin. Deforestation disturbed the environmental cycle that caused less amount of rain in São Paulo, Brazil.

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The _____ are pure forms of matter that cannot be broken down into simplier substances.
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The elements are pure forms of matter that cannot be broken down into simpler substances.
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Anastasy [175]

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colorblindness

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6 0
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What is the sequence the organs that are involved in each step of digestion
Cloud [144]

Answer:

The gastrointestinal tract comprises of Mouth-Esophagus-Stomach-Small intestine-Colon-Rectum.

Liver, pancreas and gallbladder are solid organs of digestive system.

Explanation:

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5 0
3 years ago
A population of 150 individuals has an allele frequency of 0.2 for the dominant allele (H) and a frequency of 0.8 for the recess
Amanda [17]
Hardy-Weinberg Equation (HW) states that following certain biological tenets or requirements, the total frequency of all homozygous dominant alleles (p) and the total frequency of all homozygous recessive alleles (q) for a gene, account for the total # of alleles for that gene in that HW population, which is 100% or 1.00 as a decimel. So in short: p + q = 1, and additionally (p+q)^2 = 1^2, or 1
So (p+q)(p+q) algebraically works out to p^2 + 2pq + q^2 = 1, where p^2 = genotype frequency of homozygous dominant individuals, 2pq = genotype frequency of heterozygous individuals, and q^2 = genotype frequency of homozygous recessive individuals.
The problem states that Ptotal = 150 individuals, H frequency (p) = 0.2, and h frequency (q) = 0.8.
So homozygous dominant individuals (HH) = p^2 = (0.2)^2 = 0.04 or 4% of 150 --> 6 people
Heterozygous individuals (Hh) = 2pq = 2(0.2)(0.8) = 0.32 or 32% of 150
--> 48 people
And homozygous recessive individuals (hh) = q^2 = (0.8)^2 = 0.64 = 64% of 150 --> 96 people
Hope that helps you to understand how to solve these types of population genetics problems!
6 0
3 years ago
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