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Brrunno [24]
3 years ago
12

A number decreased by 7%

Mathematics
2 answers:
Mariulka [41]3 years ago
7 0
X-7/100
OR
X-0.07
Since we don't know the number we need a variable which can be any alphabet so I chose "X".
For example if it were 7 decreased by 7 percent, it would be equal to:
7 - 7/100=6.93
Anarel [89]3 years ago
7 0
93 x
--- = ------

100 Full Number

*****************

93(full number) = 100x
Then divide by 100

*****************

Here is an Example:

93(10) = 100x
930 = 100x
Divide each side by 100

9.3


P.S
The reason the answer isn't 7 is because it's not 70%
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In the diagram below, points A, E, and F lie on the same line. If ABCDE is a regular pentagon, and \angle EFD=90^\circ, then how
mash [69]

The measure of ∠FDE = 18°

<u>Explanation:</u>

A Pentagon has 5 sides and is made of 3 triangles

So, sum of the interior angles of the triangle = 180°

Therefore, the total interior angle of a regular pentagon = 3 X 180° = 540°

A regular pentagon will have all its angle equal

All the five angles would make 540°

Let the measure of one angle = x

So,

5x = 540°

x = 108°

Therefore, the measure of each angle of a pentagon is 108°

From the diagram,

∠AED + ∠FED = 180°

∠AED = 108° as it is one of the sides of the pentagon

So,

108° + ∠FED = 180°

∠FED = 72°

In ΔEFD,

∠FED + ∠EFD + ∠FDE = 180°

72° + 90° + ∠FDE = 180°

∠FDE = 18°

Therefore, the measure of ∠FDE = 18°

8 0
3 years ago
Find the domain of each function using interval notation. (Please help I have an exam tomorrow and I’m really stuck)
stellarik [79]

Answer:

For number 9)

Interval notation (-\infty,3]

For number 10)

Interval notation: (-\infty,\frac{-1}{2}) \cup (\frac{-1}{2},\infty).

Step-by-step explanation:

On square roots you have to make sure the inside is positive or zero.

So the domain of the first one will come from solving

6-2x \ge 0

Subtract 6 on both sides:

-2x \ge -6

Divide both sides by -2 (flip inequality when divide both sides by negative):

x \le 3

The domain is less than or equal to 3.

Interval notation (-\infty,3]

On fractions you have to watch out for dividing by 0.

The domain is all real numbers except when 4x+2=0.

4x+2=0

Subtract 2 on both sides:

4x=-2

Divide both sides by 4:

x=-2/4

Reduce:

x=-1/2

The domain is all real numbers except when x=-1/2

Interval notation: (-\infty,\frac{-1}{2}) \cup (\frac{-1}{2},\infty).

5 0
4 years ago
Read 2 more answers
A broker has calculated the expected values of two different financial instruments X and Y. Suppose that E(x)= $100, E(y)=$90 SD
Sveta_85 [38]

Expectation is linear, meaning

E(<em>a X</em> + <em>b Y</em>) = E(<em>a X</em>) + E(<em>b Y</em>)

= <em>a </em>E(<em>X</em>) + <em>b</em> E(<em>Y</em>)

If <em>X</em> = 1 and <em>Y</em> = 0, we see that the expectation of a constant, E(<em>a</em>), is equal to the constant, <em>a</em>.

Use this property to compute the expectations:

E(<em>X</em> + 10) = E(<em>X</em>) + E(10) = $110

E(5<em>Y</em>) = 5 E(<em>Y</em>) = $450

E(<em>X</em> + <em>Y</em>) = E(<em>X</em>) + E(<em>Y</em>) = $190

Variance has a similar property:

V(<em>a X</em> + <em>b Y</em>) = V(<em>a X</em>) + V(<em>b Y</em>) + Cov(<em>X</em>, <em>Y</em>)

= <em>a</em>^2<em> </em>V(<em>X</em>) + <em>b</em>^2 V(<em>Y</em>) + Cov(<em>X</em>, <em>Y</em>)

where "Cov" denotes covariance, defined by

E[(<em>X</em> - E(<em>X</em>))(<em>Y</em> - E(<em>Y</em>))] = E(<em>X Y</em>) - E(<em>X</em>) E(<em>Y</em>)

Without knowing the expectation of <em>X Y</em>, we can't determine the covariance and thus variance of the expression <em>a X</em> + <em>b Y</em>.

However, if <em>X</em> and <em>Y</em> are independent, then E(<em>X Y</em>) = E(<em>X</em>) E(<em>Y</em>), which makes the covariance vanish, so that

V(<em>a X</em> + <em>b Y</em>) = <em>a</em>^2<em> </em>V(<em>X</em>) + <em>b</em>^2 V(<em>Y</em>)

and this is the assumption we have to make to find the standard deviations (which is the square root of the variance).

Also, variance is defined as

V(<em>X</em>) = E[(<em>X</em> - E(<em>X</em>))^2] = E(<em>X</em>^2) - E(<em>X</em>)^2

and it follows from this that, if <em>X</em> is a constant, say <em>a</em>, then

V(<em>a</em>) = E(<em>a</em>^2) - E(<em>a</em>)^2 = <em>a</em>^2 - <em>a</em>^2 = 0

Use this property, and the assumption of independence, to compute the variances, and hence the standard deviations:

V(<em>X</em> + 10) = V(<em>X</em>)  ==>  SD(<em>X</em> + 10) = SD(<em>X</em>) = $90

V(5<em>Y</em>) = 5^2 V(<em>Y</em>) = 25 V(<em>Y</em>)  ==>  SD(5<em>Y</em>) = 5 SD(<em>Y</em>) = $40

V(<em>X</em> + <em>Y</em>) = V(<em>X</em>) + V(<em>Y</em>)  ==>  SD(<em>X</em> + <em>Y</em>) = √[SD(<em>X</em>)^2 + SD(<em>Y</em>)^2] = √8164 ≈ $90.35

8 0
4 years ago
Geometry Angles question 3, Thanks if you help
Andre45 [30]

Answer:

54

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64 + 62 = 126

180 - 126 = 54

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