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crimeas [40]
3 years ago
13

In class of 60 boys, there are 45 boys who play card and 30 boys who play carom. How many play both games​

Mathematics
2 answers:
zalisa [80]3 years ago
6 0

Answer:

the answer is 40 boys

Step-by-step explanation:

Let's say there are x boys who play both cards and carrom.

We setup up an equation that involved all information given and x.

Boys who only play cards = 45-x

Boys who only play carrom = 20-x

Boys who play both = x

Add there together and you should get 60, which is the total number of students in the class.

(45-x)+(20-x)+x=60

65-x=60

x=5

Boys who only play cards=45-x=45–5=40

hope it helps you

Mrac [35]3 years ago
6 0

Answer:

there are 15 boys who can play both games in the class.

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Step-by-step explanation:

The given probabilities are; P(Orange) = 1/3, P(Blue) = 1/6, P(Purple) = 1/2

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a. The probability of simultaneously 'rolling a 3' and 'spinning blue', P(3 and Blue) is given as follows;

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P(rolling a 1) = 1/6, P(Orange) = 1/3

P(1 or Orange) = P(rolling a 1) + P(Orange) - P(1 and Orange)

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The total number of the bags sold by the shopkeeper will be 65532.

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Answer:

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