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3 years ago

In class of 60 boys, there are 45 boys who play card and 30 boys who play carom. How many play both games

Mathematics

2 answers:

zalisa [80]2 years ago

6 0

Answer:

the answer is 40 boys

Step-by-step explanation:

Let's say there are x boys who play both cards and carrom.

We setup up an equation that involved all information given and x.

Boys who only play cards = 45-x

Boys who only play carrom = 20-x

Boys who play both = x

Add there together and you should get 60, which is the total number of students in the class.

(45-x)+(20-x)+x=60

65-x=60

x=5

Boys who only play cards=45-x=45–5=40

hope it helps you

Mrac [35]2 years ago

6 0

Answer:

there are 15 boys who can play both games in the class.

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Step-by-step explanation:

$\text {Use the Pythagorean Theorem to solve for the leg.}\\a^2 + b^2 =c^2$

What we know:

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3 years ago

In class of 60 boys, there are 45 boys who play card and 30 boys who play carom. How many play both games​

In class of 60 boys, there are 45 boys who play card and 30 boys who play carom. How many play both games