I'm not sure I understand your question, but I believe the answer you're looking for is 57632.
Sry I'm couldn't solve the second one but the ans for the 1st is 504 sq units
Answer:
It took 1.2 hours to get to the store
Step-by-step explanation:
Let the time taken to reach the store be t₁
Let the time taken to come back be t₂
Let the speed to and from store = s₁ and s₂ respectively
let the distance to the store = d
To the store:
![speed = \frac{distance}{time} \\s = \frac{d}{t_1} \\t_1 = \frac{d}{s_1}\\t_1 =\frac{d}{4} - - - - - (1)](https://tex.z-dn.net/?f=speed%20%3D%20%5Cfrac%7Bdistance%7D%7Btime%7D%20%5C%5Cs%20%3D%20%5Cfrac%7Bd%7D%7Bt_1%7D%20%5C%5Ct_1%20%3D%20%5Cfrac%7Bd%7D%7Bs_1%7D%5C%5Ct_1%20%3D%5Cfrac%7Bd%7D%7B4%7D%20-%20-%20-%20-%20-%20%281%29)
Back from the store:
![s_2 = \frac{d}{t_2} \\t_2 = \frac{d}{s_2}\\where:\\s_2 = 6\ miles\ per\ hour\\t_2 = \frac{d}{6} - - - - - - (2)](https://tex.z-dn.net/?f=s_2%20%3D%20%5Cfrac%7Bd%7D%7Bt_2%7D%20%5C%5Ct_2%20%3D%20%5Cfrac%7Bd%7D%7Bs_2%7D%5C%5Cwhere%3A%5C%5Cs_2%20%3D%206%5C%20miles%5C%20per%5C%20hour%5C%5Ct_2%20%3D%20%5Cfrac%7Bd%7D%7B6%7D%20-%20-%20-%20-%20-%20-%20%282%29)
We are told that total time (t₁ + t₂) = 2 hours
t₁ + t₂ = eqn (1) + eqn (2)
![\frac{d}{4} + \frac{d}{6} = 2\\Multiplying\ through\ by\ 12:\\3d\ +\ 2d\ =\ 24\\5d = 24\\d = \frac{24}{5} \\d = 4.8\ miles](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B4%7D%20%2B%20%5Cfrac%7Bd%7D%7B6%7D%20%3D%202%5C%5CMultiplying%5C%20through%5C%20by%5C%2012%3A%5C%5C3d%5C%20%2B%5C%202d%5C%20%3D%5C%2024%5C%5C5d%20%3D%2024%5C%5Cd%20%3D%20%5Cfrac%7B24%7D%7B5%7D%20%5C%5Cd%20%3D%204.8%5C%20miles)
∴ length of trip to the store = t₁
from eqn (1)
![t_1 = \frac{d}{4} \\t_1 = \frac{4.8}{4} \\t_1 = 1.2\ hours](https://tex.z-dn.net/?f=t_1%20%3D%20%5Cfrac%7Bd%7D%7B4%7D%20%5C%5Ct_1%20%3D%20%5Cfrac%7B4.8%7D%7B4%7D%20%5C%5Ct_1%20%3D%201.2%5C%20hours)