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Andrei [34K]
3 years ago
7

Find the exact value of sin 30 degrees

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
5 0

Answer:

\sin( 30 )  =  \frac{1}{2}  = 0.5

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The equation for line j can be written as y= 1 2 x–4. Parallel to line j is line k, which passes through the point ( – 8, – 5).
blagie [28]
Just like this
Y=12x+91

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3 years ago
Using complete sentences, describe the net of a rectangular prism with a length of 12 centimeters, a width of 9
nikklg [1K]

Answer:

The description is as follows:

Step-by-step explanation:

The description of the net of a rectangular prism is as follows:

The length i.e. 12 centimeters would be multiplied by width of 9 and then it added to the height i.e. 5 centimeters

The above represent the description of the net of a rectangular prism

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3 years ago
A line is parallel to y = 2x - 8 and
Angelina_Jolie [31]

Answer:

the line is y=2x+7

Step-by-step explanation:

6 0
3 years ago
Find the exact values of the remaining five trigonometric functions of theta, suppose theta is an angle in the standard position
nexus9112 [7]

Answer:

\sin(\theta)=60/61\text{ and } \csc(\theta)=61/60\\\cos(\theta)=11/61\text{ and } \sec(\theta)=61/11\\\tan(\theta)=60/11\text{ and } \cot(\theta)=11/60

Step-by-step explanation:

So, we know that:

\tan(\theta)=60/11\text{ and } 90\textdegree

Since θ is in QI, this means that <em>all</em> of our trig ratios will be positive. Recall All Students Take Calculus. Since it's QI, we refer to A in All. The A tells us that all the ratios will be positive.

Now, let's figure out the remaining ratios knowing that all of them is positive. First, let's find the hypotenuse. Recall that tangent is the ratio of the <em>opposite side to the adjacent side</em>. So, we can use the Pythagorean Theorem to find the hypotenuse. So:

a^2+b^2=c^2

Substitute 60 for a and 11 for b:

60^2+11^2=c^2

Solve for c. Square both numbers:

3600+121=c^2

Add:

c^2=3721

Take the square root of both sides:

c=61

Therefore, the hypotenuse is 61.

So, our side lengths are: Opposite=60; Adjacent=11; and Hypotenuse=61.

Now that we know the lengths, we can find the other trig ratios:

Sine and Cosecant:

\sin(\theta)=opp/hyp

Substitute 60 for Opp and 61 for Hyp:

\sin(\theta)=60/61

Cosecant is the reciprocal of sine. So:

\csc(\theta)=61/60

Cosine and Secant:

\cos(\theta)=adj/hyp

Substitute 11 for Adj and 61 for Hyp:

\cos(\theta)=11/61

Secant is the reciprocal of cosine. So:

\sec(\theta)=61/11

Tangent and Cotangent:

We are already given that tangent is:

\tan(\theta)=60/11

Cotangent is the reciprocal of tangent. So:

\cot(\theta)=11/60

4 0
4 years ago
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