Step-by-step explanation:
Let y1 and y2 be (e^x)/2, and (xe^x)/2 respectively.
The Wronskian of them functions be
W = (y1y2' - y1'y2)
y1 = (e^x)/2 = y1'
y2 = (xe^x)/2
y2' = (1/2)(x + 1)e^x
W = (1/4)(x + 1)e^(2x) - (1/4)xe^(2x)
= (1/4)(x + 1 - x)e^(2x)
W = (1/4)e^(2x)
Since the Wronskian ≠ 0, we conclude that functions are linearly independent, and hence, form a set of fundamental solutions.
Answer:
3,468?
Step-by-step explanation:
I think the prompt is a little confusing, but I went with the logic of literally using the numbers and combining them.
Answer:
i believe it is f
Step-by-step explanation:
Answer:
25/2 a^2 and the alternative form 12.5a^2
Step-by-step explanation:
Answer:
Area: 272ft²
Volume = 82.6236447189ft³
Step-by-step explanation:
AREA
The area of a square pyramid is found by combining the area of the base and the area of the triangular faces:
Area of base = area of square = L² = 8² = 16ft²
Area of one triangular face = (1/2)bh = (1/2)(8)(16) = 64ft²
There are four triangular faces so the total area = 16+4(64)= 16+256= 272 ft²
VOLUME
The volume of a square pyramid = (a²)(h/3), where a is the length of the base and h is the length from the top of the pyramid to the middle of the square.
We are given a, but not h. To find h, we must imagine a right-angled triangle within the pyramid, where 16ft is the hypotenuse, h is the height and the base is half of a (since the base is a square and the distance is from the edge to the middle). We can then use pythagorus's theorem to find h:
A²=B²+C²
16²=(8/2)²+h²
256=16+h²
h=√240
h=15.4919333848ft
Knowing h, we can find the volume:
Volume = (a²)(h/3)
Volume = (8²)(15.4919333848/3)
Volume = (16)(5.16397779493)
Volume = 82.6236447189ft³
