Is there a remainder in this long division problem?
2 answers:
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To find g (f(x)) you should substitute "4x^2+x+1" to "x" of g(x) function. You'll havew:
To count (4x^2+x+1)^2 Just assume ( [4x^2+x] + 1)^2 and use the (a+b)^2=a^2+2ab+b^2 formula, where a=4x^2+x and b=1
To count (4x^2+x+1)^2 Just assume ( [4x^2+x] + 1)^2 and use the (a+b)^2=a^2+2ab+b^2 formula, where a=4x^2+x and b=1