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arlik [135]
3 years ago
14

I need someone to explain how to solve this please!

Mathematics
1 answer:
Paladinen [302]3 years ago
4 0

(x+3)/2x+5 + (3x-5)/(3x+5)

LCM = ( 2x+5)( 3x+5)

[( x+3)( 3x+5) + ( 3x -5)( 2x+5)]/( 2x+5)( 3x+5)

= (3x^2 + 5x +9 x +15 + 6x^2 + 15x -10x -25)/( 2x+5)( 3x+5)

=( 9 x^2 + 19x -10)/( 2x +5)(3x+5)

A) option

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Brrunno [24]

Answer:

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3 years ago
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IQ scores are known to be normally distributed. The mean IQ score is 100 and the standard deviation is 15. What percent of the p
Masja [62]

Answer:

47.06% of the population has an IQ between 85 and 105.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 15

What percent of the population has an IQ between 85 and 105?

This is the pvalue of Z when X = 105 subtracted by the pvalue of Z when X = 85. So

X = 105

Z = \frac{X - \mu}{\sigma}

Z = \frac{105 - 100}{15}

Z = 0.33

Z = 0.33 has a pvalue of 0.6293.

X = 85

Z = \frac{X - \mu}{\sigma}

Z = \frac{85 - 100}{15}

Z = -1

Z = -1 has a pvalue of 0.1587

So 0.6293 - 0.1587 = 0.4706 = 47.06% of the population has an IQ between 85 and 105.

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Samuel already has 56 flowers in his garden, and he can also grow 1 flower with every seed packet he uses. How many seed packets
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Answer:

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Step-by-step explanation:

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What is the binary number for 24​
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Answer:

Here im to lazy to solve so a pic  

Step-by-step explanation:

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