n = int(input("How many numbers do you need to check? "))
odd = 0
even = 0
i = 0
while i < n:
num = int(input("Enter number: "))
if num % 2 == 0:
even += 1
print(str(num)+" is an even number")
else:
odd += 1
print(str(num)+" is an odd number")
i += 1
print("You entered "+str(even)+" even number(s).")
print("You entered "+str(odd)+" odd number(s).")
I hope this helps!
The pseudocode to find the sum of all integers that are multiples of 9, from 1 to 250.
totalSum = 0
for i from 1 to 250{
if i is divided by 9 and remainder is 0{
totalSum = totalSum + i;
}
}
print(totalSum)
in python language the code will be
totalSum = 0
for i in range(1,250):
if i%9==0:
totalSum += i
If you will run the program , the answer would be 3402.
Explanation:
In general, when a program runs in text-based environment like command line interface, the program is used for determining the order in which things happen.
As the program runs, the user will not have any choice and he or she can enter the required data.
If the user enters the data in required format then, he/she can get the result or output in desired format.
