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mash [69]
3 years ago
5

Y-5x=0 need to plot points and graph

Mathematics
1 answer:
grigory [225]3 years ago
4 0
<span>Y-5x=0 is a linear equation (since the order is 1 only) in which when expressed in the standard form y = 5x, the line is inclined upward and has a slope of 5. in this case, it crosses through the points (0,0) as the y-intercept and (1/5, 0 ) as the y-intercept of the function </span>
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Pretty sure it's 21 degrees.

Step-by-step explanation:

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Step-by-step explanation:

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<em>Your question is not well presented</em>

Question:

What is the solution to the linear equation?

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Answer:

x = \frac{-5}{3}

Step-by-step explanation:

Given

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Required

Simplify

x - \frac{2}{3}x - \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x

Add \frac{1}{2} to both sides

x - \frac{2}{3}x - \frac{1}{2} + \frac{1}{2} = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

x - \frac{2}{3}x = \frac{1}{3} + \frac{5}{6}x + \frac{1}{2}

Subtract \frac{5}{6}x from both sides

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{5}{6}x + \frac{1}{2} - \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2} + \frac{5}{6}x- \frac{5}{6}x

x - \frac{2}{3}x - \frac{5}{6}x= \frac{1}{3} + \frac{1}{2}

Take LCMs

\frac{6x - 4x -5x}{6}= \frac{2+3}{6}

\frac{-3x}{6}= \frac{5}{6}

Multiply both sides by 6

6 * \frac{-3x}{6}= \frac{5}{6} * 6

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Divide both sides by -3

\frac{-3x}{-3}= \frac{5}{-3}

x = \frac{5}{-3}

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