Answer:
£976
Step-by-step explanation:
y=4x^2+5x-6y=4x2+5x−6
:
Given points are :
x = -2 0 4
y=f(x) = 0 -6 78
We have to model the parabola with the help of these points
Solution:
We consider a standard equation of parabola y= ax^2+bx+cy=ax2+bx+c
now, we put the points in the equation we get,
at (-2,0) is 4a-2b+c=0
at (0,-6) is c=-6
at (4,78) is 78= 16a+4b+c
now, solving these equation we get, a= 4 , b= 5 , c= -6
so the equation formed with these points is y=4x^2+5x-6y=4x2+5x−6
we can see this in the graph attached.
Step-by-step explanation:
Hope this helps!! :D
9514 1404 393
Answer:
2xy^2
Step-by-step explanation:
The terms are "like" so can be combined. It might be helpful to think of this as an application of the distributive property.
-3xy^2 +5xy^2 = (-3 +5)xy^2 = 2xy^2
I think it’s just asking you to add the two functions (f + g)(x)
If f(x) = sqrt x + 3
And g(x) = x + 2
Then (f + g)(x) = (sqrt x + 3) + (x +2)
And I’m pretty sure that’s all you can simplify