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tresset_1 [31]
3 years ago
15

Round 6,609,707 and 147,779 to the nearest ten thousand? Please he asap thanks

Mathematics
2 answers:
scoundrel [369]3 years ago
5 0
6,609,707 rounded to the nearest ten thousand is 6,610,000. It's because 6,609,707 is closer to 6,610,000 than to 6,600,000.

147,779 rounded to the nearest ten thousand is 150,000. It's because 147,779 is closer to 150,000 than to 140,000.
lara31 [8.8K]3 years ago
3 0
<span>Round 6,609,707 and 147,779 to the nearest ten thousand? Please he asap thanks 6610000 and 150000
hope it helps </span>
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The volume of a cube is 512 cm3 . What is the area, in square centimetres, of each side of the cube?
lesantik [10]

Answer:

Step-by-step explanation:

V of a cube is s^3

V = 512

s = cube root of (V)

s = cube root of 512 cm^3

s = 8

The area of one face of the cube is s^2

s = 8

Area 1 face = 8^2

Area of 1 face = 64 cm^2

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2 years ago
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7 0
3 years ago
George had $1,201.87 in taxable income for the last pay period. If the federal income tax rate was 15%, how much did George pay
Hatshy [7]
Just multiply the income by .15

1201.87 * .15 = 180.28

He paid $180.28

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4 0
3 years ago
A man has 33 coins in his pocket, all of which are dimes and quarters. If the total value of his change
kupik [55]

Answer:

Number of dimes = 16

Number of quarters = 17

====================================================

Work Shown:

d = number of dimes

q = number of quarters

d+q = 33 coins total, this solves to d = 33-q

10d = value of all the dimes in cents

25q = value of all the quarters in cents

10d+25q = 585 cents total

--------------

Plug in d = 33-q and solve for q

10d+25q = 585

10(33-q) + 25q = 585

330-10q+25q = 585

15q+330 = 585

15q = 585-330

15q = 255

q = 255/15

q = 17

The man has 17 quarters

d = 33-q = 33-17 = 16

He also has 16 dimes.

--------------

Check:

16 dimes + 17 quarters = 33 coins total

16 dimes = 16*10 = 160 cents

17 quarters = 17*25 = 425 cents

160 cents + 425 cents = 585 cents

The answer is confirmed.

3 0
2 years ago
Find the best approximation of the volume of the sphere.
BabaBlast [244]
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V = 4/3(3.14)(14)³
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V = 11488.21333cm³
5 0
3 years ago
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