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3 years ago

Round 6,609,707 and 147,779 to the nearest ten thousand? Please he asap thanks

2 answers:

5 0

6,609,707 rounded to the nearest ten thousand is 6,610,000. It's because 6,609,707 is closer to 6,610,000 than to 6,600,000.

147,779 rounded to the nearest ten thousand is 150,000. It's because 147,779 is closer to 150,000 than to 140,000.

lara31 [8.8K]3 years ago

3 0

Round 6,609,707 and 147,779 to the nearest ten thousand? Please he asap thanks 6610000 and 150000
hope it helps

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20 POINTS ! PLEASE HELP! 1. Design your own real-world scenario in which the solution requires the Pythagorean Theorem. Use comp

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Scenario: a worker needs to repair a window on the second floor of a building He is outside 3 feet way from the building He starts walking and when he reaches the wall he is lifted 4 feet until reaching the window What is the distance from the window to the point where he has standing before he start walking ? 2))This path forms a right triangle.2 sides are known but not the hypotenuse Formula a^=b^=c^ a=4 b=3 c=x (Hypotenuse) 3) Substitute 4^+3^=X^ 16+9=x^ 25=x^ 5=x Hypotenuse=5 The sides of the triangle formed in this situation are 4,3,and 5

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3 years ago

Juan is making a fruit salad. He has grapes, watermelon, apples, pineapple, bananas, mangoes, honeydew, and cantaloupe. He wants

nika2105 [10]

The number of ways that he can make the fruit salad if it must contain watermelon is 35.

<h3>What is Permutation and combination?</h3>

Selection of the one object from the given samples with replacement or without replacement is called as the permutation. The selection of the items from the sample as they are different with each other.

The salad contains water melon, now we have to select 4 more fruits out of 7.

Using combination

$^{n{C}_r$ = n! / r! (n-r)!

$^{7}C_4$ = 7!/ 4! (7-4)!

= 7*6*5*4! / 4! * 3*2

= 35

Hence, number of ways that he can make the fruit salad if it must contain watermelon is 35.

Learn more about Permutation and combination here:

brainly.com/question/11732255

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3 0

2 years ago

What is a linear equation of a line with slope -4 and y-intercept 7

ololo11 [35]

The equation would look like

Y=-4x+7

Y=mx+b

5 0

3 years ago

The following integral requires a preliminary step such as long division or a change of variables before using the method of par

shtirl [24]

Division yields

$\dfrac{x^4+7}{x^3+2x} = x-\dfrac{2x^2-7}{x^3+2x}$

Now for partial fractions: you're looking for constants a, b, and c such that

$\dfrac{2x^2-7}{x(x^2+2)} = \dfrac ax + \dfrac{bx+c}{x^2+2}$

$\implies 2x^2 - 7 = a(x^2+2) + (bx+c)x = (a+b)x^2+cx + 2a$

which gives a + b = 2, c = 0, and 2a = -7, so that a = -7/2 and b = 11/2. Then

$\dfrac{2x^2-7}{x(x^2+2)} = -\dfrac7{2x} + \dfrac{11x}{2(x^2+2)}$

Now, in the integral we get

$\displaystyle\int\frac{x^4+7}{x^3+2x}\,\mathrm dx = \int\left(x+\frac7{2x} - \frac{11x}{2(x^2+2)}\right)\,\mathrm dx$

The first two terms are trivial to integrate. For the third, substitute y = x ² + 2 and dy = 2x dx to get

$\displaystyle \int x\,\mathrm dx + \frac72\int\frac{\mathrm dx}x - \frac{11}4 \int\frac{\mathrm dy}y \\\\ =\displaystyle \frac{x^2}2+\frac72\ln|x|-\frac{11}4\ln|y| + C \\\\ =\displaystyle \boxed{\frac{x^2}2 + \frac72\ln|x| - \frac{11}4 \ln(x^2+2) + C}$

7 0

2 years ago

Kayla had 64b dollars. She gave 1/8 of it to Luke and spent $45. How much money did Kayla have left? Express answer in terms of

beks73 [17]

We know that
1) Kayla originally has 64b dollars
2) She gave 1/8 of it to Luke-----> (1/8)*64b=8b
in this moment Kayla has------> 64b-8b=56b
3) Kayla spent $45
in this moment Kayla has------> 56b-$45

therefore

the answer is
(56b-$45)

4 0

3 years ago

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