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zvonat [6]
3 years ago
13

Candice and christ run a relay race at recess. Candice runs 1/2 of a lap around the track. Chris runs 1/3 of a lap around the tr

ack. How much farther does candice run that chris?
Mathematics
1 answer:
eduard3 years ago
5 0

Answer:

Candice ran 1/6 of a lap further than Chris.

Step-by-step explanation:

we know that

To find out how much further Candice runs than Chris, subtract the distance Chris runs from the distance Candice runs

so

\frac{1}{2}-\frac{1}{3}=\frac{3-2}{6}=\frac{1}{6}\ lap

therefore

Candice ran 1/6 of a lap further than Chris.

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The graph shows the relationship between mass and volume for pure silver. Use the graph to determine the density of pure silver
Natalija [7]

Answer:

C. Slope and 10.49 g/cm^3

Step-by-step explanation:

We're missing the graph itself, but I can make an educated guess:

- Assuming x = volume and y = mass:

p = \frac{m}{v}

density = mass/volume

x = volume = run

y = mass = rise

mass/volume = rise/run = slope

The slope of the line (assuming the graph is purely linear) represents mass/volume, which is the formula for density.

I had to Google the density of silver itself. Do the math from the graph for a more appropriate answer, as the graph may be less scientifically precise.

7 0
3 years ago
Mathhhhhhhhhhhhhhhhhh
xxTIMURxx [149]

Answer:

formal proof

Step-by-step explanation:

https://quizlet.com/230868297/geometry-u2-review-flash-cards/

7 0
3 years ago
F(x) = 12 + x<br> X<br> f(x)<br> -3<br> -1<br> 0<br> 4<br> 6
katen-ka-za [31]

9514 1404 393

Answer:

  (-3, 9), (-1, 11), (0, 12), (4, 16), (6, 18)

Step-by-step explanation:

The function definition tells you that adding 12 to the x-value will give you the value of f(x).

  -3 +12 = 9, for example

The (x, f(x)) values for the table are shown above.

7 0
2 years ago
At a school fair, students were challenged to hit one of the small congruent circles on the large rectangular board with a ball.
shtirl [24]

Answer:

~4.7%

Step-by-step explanation:

Area of the rectangle: 35*52=1820

Area of 1 small circle: A=πr2=π·32≈28.27433

28.27433*3=84.82299

84.82299/1820=0.04660603846

Therefore, about 4.7%

6 0
2 years ago
Quit smoking: In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.
Flauer [41]

Answer:

The p-value of the test is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

Step-by-step explanation:

Test if less than half of HIV-positive smokers have used a nicotine patch:

At the null hypothesis, we test if the proportion is of at least half, that is:

H_0: p \geq 0.5

At the alternative hypothesis, we test if the proportion is below 0.5, that is:

H_1: p < 0.5

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that \mu = 0.5, \sigma = \sqrt{0.5*(1-0.5)} = 0.5

In a survey of 444 HIV-positive smokers, 202 reported that they had used a nicotine patch to try to quit smoking.

This means that n = 444, X = \frac{202}{444} = 0.455

Value of the test statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.455 - 0.5}{\frac{0.5}{\sqrt{444}}}

z = -1.9

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.455, which is the p-value of z = -1.9.

Looking at the z-table, z = -1.9 has a p-value of 0.0287.

The p-value is of 0.0287 < 0.05(standard significance level), which means that it can be concluded that less than half of HIV-positive smokers have used a nicotine patch.

5 0
3 years ago
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