Answer:
The answer is A I hope this helps, if not I apologize.
Explanation:
Answer:
- common = []
- num1 = 8
- num2 = 24
- for i in range(1, num1 + 1):
- if(num1 % i == 0 and num2 % i == 0):
- common.append(i)
- print(common)
Explanation:
The solution is written in Python 3.
Firstly create a common list to hold a list of the common factor between 8 and 24 (Line 1).
Create two variables num1, and num2 and set 8 and 24 as their values, respectively (Line 3 - 4).
Create a for loop to traverse through the number from 1 to 8 and use modulus operator to check if num1 and num2 are divisible by current i value. If so the remainder of both num1%i and num2%i will be zero and the if block will run to append the current i value to common list (Line 6-8).
After the loop, print the common list and we shall get [1, 2, 4, 8]
Illegal access to a system
Answer:
Option D is correct.
Explanation:
Option D is correct because when the condition if (list[j] < temp) is tested it only gets true when element in list[] array at <em>jth</em> position is less than the value in <em>temp</em> and after that it increments the value of c by this statement: c++ and so c is incremented from 0 to as much times as much elements in list[] are lesser than temp.
The answer is <span>Digital data
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