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olya-2409 [2.1K]
3 years ago
6

The equation of the circle with center (3, -2) and radius 7 is: user: enter in standard form the equation of the line passing th

rough the given point and having the given slope. b(2, - 5), m = -2/3
Mathematics
1 answer:
AURORKA [14]3 years ago
7 0
X^2+y^2-6x+2y-36=0. Use the equation of the circle (x-h)^2+(y-k)^2=radius^2, center (h,k) is (3,-2)
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Cual es resultado de 8.5 × 10^4 - 3.0 × 10^3
Veronika [31]
Simplify 10^4 to 10000

8.5x10000-3.0x10^3

Simplify 8.5x*10000 to 85000x
85000x-3.0*10^3
Simplify 3.0x10^3 to 3*10^3
Answer 85000x-3*10^3
5 0
3 years ago
I need help with this problem.
Alekssandra [29.7K]
A and 0 both equals 45 degrees
3 0
3 years ago
Read 2 more answers
X-5y=55 slope intercept form
Talja [164]

Answer:

y = x/5 -11

Step-by-step explanation:

y = mx + b (slope intercept form)

5y = x-55

y = x/5 -11

4 0
3 years ago
The slope of a linear function is 1/5. For every rise of 5 units, what is the run?
Jlenok [28]

Answer:

for every rise of 1 the run would be 25

7 0
3 years ago
Paul is saving for a down payment to buy a house. The account earns 13% interest compound quarterly, and he wants to have $15,00
Tatiana [17]

Answer:

The principal must be = $8991.88

Step-by-step explanation:

Formula for compound interest is:

A = P(1 + \frac{r}{n})^{nt}

Where A is the amount after 't' years.

P is the principal amount

n is the number of times interest is compounded each year.

r is the rate of interest.

Here, we are given that:

Amount, A = $15000

Rate of interest = 13 % compounded quarterly i.e. 4 times every year

Number of times, interest is compounded each year, n = 4

Time, t = 4 years.

To find, Principal P = ?

Putting all the given values in the formula to find P.

15000 = P(1 + \frac{13}{400})^{4\times 4}\\\Rightarrow 15000 = P(1 + 0.0325)^{16}\\\Rightarrow 15000 = P(1.0325)^{16} \\\Rightarrow 15000 = P \times 1.66817253\\\Rightarrow P = \dfrac{15000}{1.66817253}\\\Rightarrow P \approx \$8991.88

So, <em>the principal must be = $8991.88</em>

4 0
3 years ago
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