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slamgirl [31]
3 years ago
12

Does x equal if the problem is negative x -4x - 7 equals 5 negative 2X

Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0

Answer:

X = - 4

Step-by-step explanation:

Given in problem

- x -4x - 7 = 5 -2x

Or, -5x - 7 = 5- 2x

Or, -5x + 2x = 5 + 7

Or, -3x = 12

Or, x = - \frac{12}{3}

∴ X = - 4    Answer

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Match each expression to its equivalent standard form.
Aleksandr [31]

Let's expand the products they are all in the form

(a+b)(a-b)=a^2-b^2

For the first one we have a=x and b=2i:

(x+2i)(x-2i)=x^2-(2i)^2=x^2+4

For the second one we have a=x-2 and b=2i:

(x-2+2i)(x-2-2i)=(x-2)^2-(2i)^2 = x^2-4x+4+4=x^2-4x+8

For the third one we have a=x+1 and b=i:

(x+1+i)(x+1-i)=(x+1)^2-i^2=x^2+2x+1+1=x^2+2x+2

3 0
3 years ago
There are 1 1/2 cups of flour and 2 eggs. How would you write the ratio that compares the cups of flour to eggs?
MArishka [77]

Answer:

1 1/2 to 2

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
A school principal has to choose randomly among the six best students in each grade to be the school captain every month. For th
schepotkina [342]

Answer: It's an unfair method because two or more students could get the same results./ D

Step-by-step explanation: hope this helps

4 0
2 years ago
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License plate numbers come in a variety of styles. (Ignore the fact that some choices of letters could not be used because they
avanturin [10]
Five digit is the answer
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3 years ago
A certain car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year
icang [17]

Answer:

b(b/a)^2

Step-by-step explanation:

Given that the value of the car depreciates such that its value at the end of each year is p % less than its value at the end of the previous year and that car was worth a dollars on December 31, 2010 and was worth b dollars on December 31, 2011, then

b = a - (p% × a) = a(1-p%)

b/a = 1 - p%

p% = 1 - b/a = (a-b)/a

Let the worth of the car on December 31, 2012 be c

then

c = b - (b × p%) = b(1-p%)

Let the worth of the car on December 31, 2013 be d

then

d = c - (c × p%)

d = c(1-p%)

d = b(1-p%)(1-p%)

d = b(1-p%)^2

d = b(1- (a-b)/a)^2

d = b((a-a+b)/a)^2

d = b(b/a)^2 = b^3/a^2

The car's worth on December 31, 2013 =  b(b/a)^2 = b^3/a^2

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