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-BARSIC- [3]
4 years ago
15

Round 0.1347 to the nearest tenth. Do not write extra zeros.

Mathematics
2 answers:
Katena32 [7]4 years ago
8 0
The number would be rounded to 0.1
IgorLugansk [536]4 years ago
7 0
0.1347 rounded to nearest tenth is 0.1
1 is in the tenth place
3 is in the hundredth place
4 is in the thousandth place
and so on
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Due in 30 min pls help
andre [41]

Answer:

5 i think the anwser is 5 i did my best

3 0
3 years ago
If the equation of a circle is (x + 5)2 + (y - 7)2 = 36, its radius is:
andrey2020 [161]

Answer:

6

Step-by-step explanation:

The number on the right side of the equal side represents the radius, HOWEVER, it is squared, therefore you must square root it to get 6

5 0
4 years ago
If w = 6 units, x = 3 units, and y = 5 units, what is the surface area of the figure?
Dima020 [189]

*see attachment for the diagram

Answer:

A. 178 units²

Step-by-step explanation:

Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)

✔️Surface area of the square pyramid = s² + 2*s*l

Where,

s = side length of square base (w) = 6 units

l = slant height = ?

Use Pythagorean theorem to find l

l = √((w/2)² + y²)

l = √((6/2)² + 5²) = √(9 + 25)

l = √34

l ≈ 5.8 units

Surface area of the square pyramid = 6² + 2*6*5.8 = 105.6 units²

✔️Surface area of square prism:

SA = 2a² + 4ah

Where,

a = w = 6 units

h = x = 3 units

Substitute

SA = 2(6²) + 4*6*3

= 72 + 72

= 144 units²

✔️base area of the square pyramid = s²

s = w

Base area = 6²

Base area = 36 units²

✅Surface area of the figure = (surface area of the square pyramid + surface area of the square prism) - 2(base area of the square pyramid)

Surface area of the figure = (105.6 + 144) - 2(36)

= 249.6 - 72

= 177.6

≈ 178 units²

7 0
3 years ago
10x^3 y^-5 z^-2 if x=3 y=2 and z=5 express your answer as a reduced fraction
sineoko [7]

Answer:

\large\boxed{\dfrac{27}{80}}

Step-by-step explanation:

Put x = 3, y = 2 and z = 5 to the given expression 10x^3y^{-5}z^{-2}:

10(3^3)(2^{-5})(5^{-2})\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\\\\=\dfrac{10(27)}{(2^5)(5^2)}=\dfrac{270}{(32)(25)}=\dfrac{270}{800}=\dfrac{27}{80}

7 0
3 years ago
A contractor buys 16 and 3/10 tons of sand and uses 8 and 4/5 tons.how much sand is left?
Andreas93 [3]

Answer:

7.5 short tons

Step-by-step explanation:

16 3/10 - 8 4/5 = 7.5

7 0
4 years ago
Read 2 more answers
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