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3 years ago

14.849 rounded to the nearest hundredth is

Mathematics

2 answers:

NeX [460]3 years ago

7 0

Answer:

14.900

Step-by-step explanation:

in 849 the 9 is not under 5 so we move it up and make the 4 a 5 and then its exactly five so we can make the 8 a 9 then cancel everything below it to a zero.

Agata [3.3K]3 years ago

6 0

Answer:

14.90 or just leave it at 14.85

Step-by-step explanation:

14.849 because it is a nine, you round up but it's a little different,

14.85 and because 4 is a 5 now,

14.90 you round up.

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Answer these for me please pretty please

anzhelika [568]

Answer:

1. t = 48.654

2. $x = \frac{8}{3}$

3. $s = \frac{49}{4}$

4. $y = \frac{19}{12}$

Step-by-step explanation:

To solve equations using variables, perform inverse operations to undo each part and isolate the variable.

1. $\frac{t}{5.4} =9.01$

Multiply by 5.4 on both sides to undo division.

t = 9.01 * 5.4

t = 48.654

2. $\frac{3}{4}x = 2$

Multiply both sides by the reciprocal of 3/4 which is 4/3.

$x = 2*\frac{4}{3} \\x = \frac{8}{3}$

3. $s + \frac{1}{4} = 12\frac{1}{2}$

Convert 12 1/2 into an improper fraction.

$s + \frac{1}{4} = \frac{25}{2}$

Subtract 1/4 from both sides.

$s + \frac{1}{4} - \frac{1}{4} = \frac{25}{2} - \frac{1}{4}$

To subtract fractions without common denominators, convert 25/2 into a fraction with denominator of 4.

$s = \frac{50}{4} - \frac{1}{4}\\s = \frac{49}{4}$

4. $2\frac{2}{3} + y = 4 \frac{1}{4}$

Subtract 2 2/3 from both sides.

$2\frac{2}{3} - 2\frac{2}{3} + y = 4 \frac{1}{4}- 2\frac{2}{3}$

Convert each fraction into improper fractions and then to common denominators.

$y = \frac{17}{4} - \frac{8}{3}\\\\ y = \frac{51}{12} - \frac{32}{12} \\\\y = \frac{19}{12}$

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4 years ago

which answer choice is it?

qwelly [4]

Answer:

Step-by-step explanation:

∠ AOC = 90° and

∠ AOB + ∠ BOC = ∠ AOC , that is

x + 8 + 2x = 90

3x + 8 = 90 ( subtract 8 from both sides )

3x = 82 ( divide both sides by 3 )

x = $\frac{82}{3}$

Then

∠ BOC = 2x = 2 × $\frac{82}{3}$ = $\frac{164}{3}$ ≈ 54.67° ( to 2 dec. places )

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