2+3i divided by 3-3i ( a+bi form)

1 answer:

6 0

$(2+3i):(3-3i)=\frac{2+3i}{3-3i}\cdot\frac{3+3i}{3+3i}=\frac{(2+3i)(3+3i)}{(3-3i)(3+3i)}=\frac{6+6i+9i-9}{3^2-(3i)^2}=\frac{-3+15i}{9+9}\\\\=\frac{-3+15i}{18}=-\frac{3}{18}+\frac{15i}{18}=-\frac{1}{6}+\frac{5}{6}i$

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In the half-angle formula for sine and cosine, notice that a plus/minus sign appears in front of each radical (square root). Whether your answer is positive or negative depends on which quadrant the new angle (the half angle) is in

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3 years ago

The heights (measured in inches) of men aged 20 to 29 follow approximately the normal distribution with mean 69.3 and standard d

Zolol [24]

Answer:

The middle 92% of all heights fall between 64.4 inches and 74.2 inches.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 69.3, \sigma = 2.8$

Between what two values does that middle 92% of all heights fall?

The middle 92% falls from X when Z has a pvalue of 0.5 - 0.92/2 = 0.04 to X when Z has a pvalue of 0.5 + 0.92/2 = 0.96. So from the 4th percentile to the 96th percentile.

4th percentile

X when $Z = -1.75$