The answer to your problem is question 3 i just took that test i got it right
Whats the experiment? there's no experiment here
Answer:
The oxygen dissociation curve represents the percentage saturation of Hb with oxygen at different partial pressure of oxygen. The different partial pressures gives sigmoid shapes to the curve. When this curves shifts to right, it indicates low affinity or binding of oxygen by the Hb. it also indicates the unloading or releases of Oxygen by Hb molecules at condition of low pressure. e,g in the muscles during strenuous exercise.However, when the curve shifts to the left, this indicate high affinity for oxygen, great binding, at high partial pressure of oxygen.e,g in the lungs to take oxygen and releases CO2.
Therefore in this scenario, the statement -. <u>During strenuous exercise, the oxygen-hemoglobin dissociation curve shifts to the right.</u> is correct. because oxygen is needed by the muscles therefore ,oxygen should be less binded by Hb, decrease affinity and easily unloaded to muscles.
<u>The statement </u>This rightward shift reflects an increase in the affinity of hemoglobin for oxygen and favors loading of O2 into hemoglobin in the lungs is wrong.
As explained above the rightwards shift indicated low affinity of Hb for oxygen(unloading)and favours unloading at the muscles because during strenuous exercise the partial pressure of oxygen is very low(but that of CO2 high) in the muscles which favours low oxygen molecules binding by Hb, and easy release to respiring cells.
Explanation:
Answer:
<h2>e) 3/4
</h2>
Explanation:
As given;
Black (B) is dominant over red (b), so B is dominant over b.
Solid (S) is dominant over spotted color(s), so S is dominant over s.
Offspring of BBss and bbss individuals are:
Gametes of parent BBss are Bs, Bs and gamete of bbss are bs, bs
offspring are : all Bbss
Cross between these offspring is; Bbss×Bbss
Gametes of parent Bbss are: Bs and bs as given that the genes are linked.
Bs, bs × Bb, bs
Offspring are = BBss, Bbss, Bbss, bbss
Black spotted (B_ss) = 3/4
