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Advocard [28]
4 years ago
12

What number is 35% of 600

Mathematics
1 answer:
emmainna [20.7K]4 years ago
4 0
35% of 600 = .35 x 600 = 210

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13. Find the equations of the straight lines which passes
ipn [44]

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Answer:

  • y = 1/2x +2
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Step-by-step explanation:

The slope of a line is the tangent of the angle it makes with the x-axis. The given line has a slope of -1/3, so the lines we want will have slopes of ...

  m1 = tan(arctan(-1/3) +45°) = 0.5 . . . . . using a calculator

  m2 = tan(arctan(-1/3) -45°) = -2

Of course, these two lines are perpendicular to each other, so their slopes will have a product of -1: (0.5)(-2) = -1.

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We can use the point-slope form of the equation for a line to write the desired equations:

  y = m(x -h) +k . . . . . line with slope m through point (h, k)

<u>Line 1</u>:

  y = 1/2(x -2) +3

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<u>Line 2</u>:

  y = -2(x -2) +3

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3 0
3 years ago
Identify the value of c in the following quadratic function f (x) = -2x^2+ 3x – 4
Hitman42 [59]

Answer:

-4

Step-by-step explanation:

Given function

f(x) = -2x² + 3x - 4

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c = - 4

Hope it will help :)❤

5 0
3 years ago
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Find the center and radius of the circle whose diameter has an endpoint at (-3, -4) and the origin.
Zina [86]

Given end points of diameter,

(x1,y1)=(-3,-4)

(x2,y2)=(0,0)

Now,

the equation of circle is,

(x-x1)(x-x2)+(y-y1)(y-y2)=0

or, (x+3)(x-0)+(y+4)(y-0)=0

or, x^2 +3x +y^2 +4y =0

or, x^2 +y^2 +3x + 4y=0

which is in the form of x^2 +y^2 +2gx +2fy + c=0

where,

g=3/2

h=2

c=0

Now,

radius(r) =  \sqrt{ {g}^{2}  +  {f}^{2} - c  } \\  =  \sqrt{ \frac{ {3}^{2} }{ {2}^{2} } +  {2}^{2}  - 0 }  \\  =  \sqrt{ \frac{9}{4}  + 4}  \\  =   \sqrt{ \frac{25}{4} }  \\  =  \frac{5}{2}

6 0
3 years ago
A single die is rolled twice. The set of 36 equally likely outcomes is {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2, 1),
prisoha [69]
24/36 which simples down to 2/3 ever 2 in 3 roles
5 0
3 years ago
What do you call an event where it doesn’t effect the other?<br> A. Dependent<br> B. Independent
devlian [24]
Independent. No need to thank me.
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3 years ago
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