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Ne4ueva [31]
3 years ago
7

Which reactions are oxidation-reduction reactions? Check all that apply

Chemistry
1 answer:
tia_tia [17]3 years ago
4 0

2 Na + Cl₂ → 2 NaCl

Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag

CH₄ + 2 O₂ → CO₂ + 2 H₂O​

are oxidation-reduction reactions

Explanation:

In the oxidation-reduction reaction there is a component which accept electrons and it is reduced and another component which donates electrons and it is oxidized.

Now in the case of the reaction of copper (Cu) with silver nitrate (AgNO₃):

Cu + 2 AgNO₃ → Cu(NO₃)₂ + 2 Ag

Cu⁰ with a oxidation number 0 donates 2 electrons⁻ and is transformed in Cu⁺² with the oxidation number 2+.

Ag⁺ with a oxidation number 1+ accepts 1 electron⁻ and is transformed in Ag with the oxidation number 0.

In the case of CH₄ + 2 O₂ → CO₂ + 2 H₂O​ reaction we have:

C⁴⁻ with a oxidation number +4 donates 8 electrons⁻ and is transformed in C⁴⁺ with the oxidation number 4+.

O⁰ with a oxidation number 0 accepts 2 electrons⁻ and is transformed in O²⁻ with the oxidation number 2-.

And in the case of 2 Na + Cl₂ → 2 NaCl reaction we have:

Na⁰ with a oxidation number 0 donates 1 electron⁻ and is transformed in Na⁺ with the oxidation number 1+.

Cl⁰ with a oxidation number 0 accepts 1 electron⁻ and is transformed in Clwith the oxidation number 1-.

Learn more about:

oxidation-reduction reactions

brainly.com/question/4222605

brainly.com/question/10725245

brainly.com/question/10211542

#learnwithBrainly

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Answer:

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In order to do that lets set up the ICE table helper which accounts for the species at equilibrium:

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Equilibrium, M    0.40 - x                              x                               x

Lets express these concentrations in terms of the equilibrium constant:

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Now the equilibrium constant is so small ( very little dissociation of HA ) that is safe to approximate 0.40 - x to 0.40,

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Note: when the aprroximation is greater than 5 % we will need to solve the resulting quadratic equation.

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