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kakasveta [241]
3 years ago
14

If a right triangle, the acute angles measure x+15 and 2x degrees. What is the measure of the smallest angle of the triangle?

Mathematics
1 answer:
saveliy_v [14]3 years ago
6 0

Answer:

The measure of the smallest angle of the triangle is  40.

Step-by-step explanation:

A right triangle adds up to 180

x+15+2x+90=180

Combine like terms

3x+105=180

Subtract both sides by 105

3x+105=180

   -105=-105

___________

3x=75 Divide by 3

x=25

Plug in 25 for x for equation expression

90=90

25+15=40

2(25)=50

Therefore for the smallest angle is 40

Hope this helps

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Which inequality about the number line shown below is true
evablogger [386]

Answer:

option D

Step-by-step explanation:

D is equal to 0 that is greater than B which is -2 by theory

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Find all x-intercepts of the function.<br> y = x³ - 9x² + 18x
iris [78.8K]

Answer:

Step-by-step explanation:

X-intercepts mean y=0 so we have

y = x³ - 9x² + 18x = 0

Factoring

x³ - 9x² + 18x = 0

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A postulate is a conjecture that has been proved to be true.
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3 years ago
Please help im so confused?
sattari [20]
Lets get started :)

The area formula of a cylinder is:
Area = 2(radius)^2+2 \pi (radius)(height)

We are given:
The radius: 6 units
The height: 15 units

Apply the formula!

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Your answer will be option D

3 0
3 years ago
What are the solutions of x^2-2x+5=0
sweet [91]

The solution of x^{2}-2 x+5=0 are 1 + 2i and 1 – 2i

<u>Solution:</u>

Given, equation is x^{2}-2 x+5=0

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}  --- (1)

<em><u>Let us determine the nature of roots:</u></em>

Here in x^{2}-2 x+5=0 a = 1 ; b = -2 ; c = 5

b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16

Since b^2 - 4ac < 0 , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}

On solving we get,

x=\frac{2 \pm \sqrt{4-20}}{2}

x=\frac{2 \pm \sqrt{-16}}{2}

x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}

we know that square root of -1 is "i" which is a complex number

\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0
3 years ago
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