Answer:
Seven
Step-by-step explanation:
Let G7, G8, and G9 be the numbers of students in the respective grades.
Then, G7 + G8 + G9 = LCM of G8 and G9
<em>Data:
</em>
G8 = 5
G9 = 3
<em>Calculations:
</em>
<em>Multiples of 5</em>: 1 2 10 15
<em>Multiples of 3</em>: 1 3 6 9 15
The <em>LCM</em> of 5 and 3 is 15.
G7 + 5 + 3 = 15 Combine like terms
G7 + 8 = 15 Subtract 8 from each side
G7 = 7
There are seven students in Grade 7.
what multiplied by what is 15 but added together is 8
......................................................
Answer: a
Answer:
B = 61.0
Step-by-step explanation:
Since this is a right angle, we can use trig functions
sin theta = opp side/ hypotenuse
sin B = 7/8
Take the inverse of each side
sin ^-1 ( sin B) = sin ^ -1 (7/8)
B =61.04497563
To the nearest tenth
B = 61.0
