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Elodia [21]
3 years ago
11

What is the width of a rectangle with an area of 5/8 inches2 and a length of 1o inches

Mathematics
1 answer:
Nata [24]3 years ago
5 0
I hope this helps you



Area=length.width



Area=1.5/8



Area=5/8
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Find the vectors T, N, and B at the given point. r(t) = < t^2, 2/3t^3, t >, (1, 2/3 ,1)
maxonik [38]

Answer with Step-by-step explanation:

We are given that

r(t)=< t^2,\frac{2}{3}t^3,t >

We have to find T,N and B at the given point t > (1,2/3,1)

r'(t)=

\mid r'(t) \mid=\sqrt{(2t)^2+(2t^2)^2+1}=\sqrt{(2t^2+1)^2}=2t^2+1

T(t)=\frac{r'(t)}{\mid r'(t)\mid}=\frac{}{2t^2+1}

Now, substitute t=1

T(1)=\frac{}{2+1}=\frac{1}{3}

T'(t)=\frac{-4t}{(2t^2+1)^2} +\frac{1}{2t^2+1}

T'(1)=-\frac{4}{9}+\frac{1}{3}

T'(1)=\frac{1}{9}=

\mid T'(1)\mid=\sqrt{(\frac{-2}{9})^2+(\frac{4}{9})^2+(\frac{-4}{9})^2}=\sqrt{\frac{36}{81}}=\frac{2}{3}

N(1)=\frac{T'(1)}{\mid T'(1)\mid}

N(1)=\frac{}{\frac{2}{3}}=

N(1)=

B(1)=T(1)\times N(1)

B(1)=\begin{vmatrix}i&j&k\\\frac{2}{3}&\frac{2}{3}&\frac{1}{3}\\\frac{-1}{3}&\frac{2}{3}&\frac{-2}{3}\end{vmatrix}

B(1)=i(\frac{-4}{9}-\frac{2}{9})-j(\frac{-4}{9}+\frac{1}{3})+k(\frac{4}{9}+\frac{2}{9})

B(1)=-\frac{2}{3}i+\frac{1}{3}j+\frac{2}{3}k

B(1)=\frac{1}{3}

5 0
3 years ago
A space shuttle orbits Earth at a speed of 21,000 km/hr. How far will it travel in 5 hours?
tresset_1 [31]
<span>21,000*5
since it travels 21,000 per hour and there is five hours. it's just simple substitution.
105,000 is the correct answer.</span>
7 0
3 years ago
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Morgarella [4.7K]

Answer:

375

Step-by-step explanation:500 equals 100% divide by 4 its 125 times 3 equals 375, your welcome

7 0
3 years ago
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I need help plz<br> ASA <br> SSA <br> SAS<br> AAS
Lera25 [3.4K]

Answer:

SAS,

Step-by-step explanation:

2 sides and the included angle.

4 0
2 years ago
(11x + 2y) - (5x – y)
omeli [17]

Answer:

the answer is 6x+3y

Step-by-step explanation:

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hope this helps :)

Try using Symbolab, I use it all the time it gives the correct answer and it gives good explanations.

5 0
3 years ago
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