Answer:
2,586
Step-by-step explanation:
Add 1000+1000
2000
Since its 999 not 1000 subtract 1
1999
Now add 1 and subtract 1 from 587
Then add 2000 with 586
2,586
Answer:
B = 61°
A = 29°
a = 10
Step-by-step explanation:
We are given;
c = 16, b = 14
Since we are told that C is a right angle, it means that C = 90°
Thus using sine rule, we have;
c/sin C = b/sin B
16/sin 90 = 14/sin B
16/1 = 14/sin B
sin B = 14/16
sin B = 0.875
B = sin^(-1) 0.875
B ≈ 61°
Now, since C is a right angle, it means that c will be the hypotenuse of the triangle.
Thus, from pythagoras theorem, If the other side of the triangle is a, then;
a² + b² = c²
a² + 14² = 16²
a² = 16² - 14²
a² = 256 - 156
a² = 100
a = √100
a = 10
Since we know B and C, we can find A because sum of angles in a triangle is 180°.
Thus;
A = 180 - (B + C)
A = 180 - (61 + 90)
A = 29°
Answer:
x = 1 y = -4
Step-by-step explanation:
- Plug the value of y into the other equation.
x + 3y = -11
x + 3(-4x) = -11
x - 12x = -11
-11x = -11
x = 1
- Now substitute the value of x into any equation.
y = -4x
y = -4(1)
y = -4
Answer:
34
Step-by-step explanation:
so 56 -89 is 23
e3 - y7 divided by the quotient is 7
Answer:



Step-by-step explanation:
Given




Required
The dimension that minimizes the cost
The volume is:

This gives:

Substitute 


Make H the subject


The surface area is:
Area = Area of Bottom + Area of Sides
So, we have:

The cost is:



Substitute:
and 



To minimize the cost, we differentiate

Then set to 0


Rewrite as:

Divide both sides by W

Rewrite as:

Solve for 


Take cube roots

Recall that:







Hence, the dimension that minimizes the cost is:


